Question

Goal is to find nth Fibonacci number. Indexing needs to start at 0. The program has to look like the example and I am having trouble programing something that willwork. Also, it must ask if the user would like to find another number at the end. Can someone please help?!? It must be in MIPS assembly programing, not Java.

Example:

Which Fibonacci number do you want: 7
Output: Number is 13 and the series is 0, 1, 1, 2, 3, 5, 8, 13
Do you want another Fibonacci number? Enter 1 for YES and 0 for NO

Answer 1

# include<stdio.h>
int main
{
int a,b,c,i,n;
scanf("%d",&n);
f(0)=0
f(1)=1
if (n=0)
printf("0")
if (n=1)
printf("1")
else
for (i=2;i<n;i++)
{ f(i)=f(i-1)+f(i-2);
f(i)=b

}
printf ("%dn",b);
printf("do u want another no");
}