Question

Problem 3

A particular brand of diet margarine was analyzed to determine the level of polyunsaturated fatty acid (in percentages). A sample of six packages resulted in the following data: 16.8, 17.2, 17.4, 16.9, 16.5, 17.1.

Question 7 0.5 pts For problem 3 what is the p-value? Almost zero Between 0.01 and 0.025 Between 0.025 and 0.05 Between 0.4 and 0.5 Question8 0.5 pts For problem 3, at a significance level of a-0.05, the company should fail to reject the null hypothesis. accept the null hypothesis. reject the null hypothesis. None of the above

Answer 1

(7) Almost zero From the given information, sample size-6, 12 sample mean x-.-16.983. sample standard deviations = 1-Σ(x,-x)2-0.3189 Null hypothesis Ho: A- Alternative hypothesis Ha , щ# The test statistic tal- degrees of freedom (n-1)-6-1-5 P- Value 2Pt td)0.000, P- Value 0.000 less than the level of significance α= 0.05. We reject the null hypothesis Level of significance α-0.05, then the critical values are-to025,6-1)--2571 and t (00256-1) = 2.571 (8)reject the null hypothesis P-value is less than the level of significance α-0.05. we reject the null hypothesis