Question

pH Ht! B C mL of titrating reagent in buret →

9. For the titration of 100.0 mL of 0.0500 M NH, with 0.100 M HCI, the curve will look different he diagram on the other side

ANSWER NUMBER 9 ONLY

SHOW ALL WORK

pH Ht! B C mL of titrating reagent in buret →

9. For the titration of 100.0 mL of 0.0500 M NH, with 0.100 M HCI, the curve will look different he diagram on the other side of this page (see your answer to question 7). Considering the than t points to be in corresponding places to the curve presented for question 8, calculate parts a-f from question 8 for this titration. Point D will be the only equivalence point. Consider po be the same mL from D as B is from A. When you are finished, draw the curve. int E to
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Po c-n 3 2 3L

3.06 enat psi_ Aウ「o.ay1 Volume 1.85 5C25 5-1.25 1.25 1.a 5 3.15 Anj し1:25Tota Vo 0 039 -9.3 10-9.3-X 0.037 4.12x10 ュ Point D fna - 60 -5.39 at poi mell t nu-, o.lo 츠 62.5-2) 6.25 135 -3Volume o n at 6-9-77- Volume /25 Vo lune 62.5 20 3。Nuon.yo 5° 6° 궈

Add a comment
Know the answer?
Add Answer to:
PH Ht! B C mL of titrating reagent in buret → 9. For the titration of 100.0 mL of 0.0500 M NH...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A) Assume that you are titrating 60.0 mL of 0.0500 M ammonia (Kb = 1.8 ×...

    A) Assume that you are titrating 60.0 mL of 0.0500 M ammonia (Kb = 1.8 × 10–5) with 0.100 M hydrochloric acid.    How much HCl (in mL) is required to reach a titration equivalence point? B) Assume that you are titrating 60.0 mL of 0.0500 M ammonia (Kb = 1.8 × 10–5) with 0.100 M hydrochloric acid. Setting up I.C.E charts for NH3 before the titration, and when the titration reaches the equivalence point.  Based on the I.C.E. Chart and find...

  • Sketch a titration curve for the titration of 25.0 mL of 0.100 M NaOH with 0.0500...

    Sketch a titration curve for the titration of 25.0 mL of 0.100 M NaOH with 0.0500 M HCl. Locate the equivalence point for each of the titration curves in problem 1.

  • • example: Titration of 100.0 mL of 0.05 M NH3 with 0.10 M HCI • Calculate...

    • example: Titration of 100.0 mL of 0.05 M NH3 with 0.10 M HCI • Calculate equivalence point volume • Calculate pH at the following volumes of acid added • 10.0 mL • 25.0 mL • 50.0 mL • 60.0 mL • Check your answers against the titration curve 

  • 3) The following plot shows two titration curves, each representing the titration of 50.00 mL of...

    3) The following plot shows two titration curves, each representing the titration of 50.00 mL of 0.100 M acid with 0.100 M NaOH. Use this graph for question 3a. [12 pts] 14 10 3 6 4 2 0 0 200 40.0 60.0 30.0 100.0 ml of 0.100 M Nadded a. i) Which point, a-d, represents the equivalence point for the titration of a weak acid? [2 pts] ii) Which point, a-d, represents the equivalence point for the titration of a...

  • Q2 Part B What is the pH at the equivalence point in the titration of 100.0...

    Q2 Part B What is the pH at the equivalence point in the titration of 100.0 mL of 0.0500 M HOCI (Ka = 3.5 x 10-8) with 0.400 M NaOH? Express your answer to two decimal places. ΤΕΙ ΑΣΦ ? pH = 19.76 Submit Previous Answers Request Answer X Incorrect; Try Again A certain weak acid, HA, with a Ka value of 5.61 x 10-6, is titrated with NaOH. Part A A solution is made by titrating 8.00 mmol (millimoles)...

  • Consider the titration of 40.0 mL of 0.500 M NH, with 1.00 M HC a) What...

    Consider the titration of 40.0 mL of 0.500 M NH, with 1.00 M HC a) What is the initial pH of the NHg(aq)? b) What is the pH halfway to the equivalence point? c) What is the volume of HCI needed to reach the equivalence point? What is the pH at the equivalence point? d) Sketch the titration curve. Label the point(s) where there is a A) a weak base B) weak acid C) Buffer D) Strong acid in excess,...

  • Consider the titration of 100.0 mL of 0.100 M /hydrazine () by 0.200 M . Assume...

    Consider the titration of 100.0 mL of 0.100 M /hydrazine () by 0.200 M . Assume that hydrazine is monoprotic. Determine the following: a. pH before any HNO3 is added b. volume of acid to reach the equivalence point c. pH when 20.0 mL of HNO3 has been added d. pH when 25.0 mL of HNO3 has been added e. pH when 40.0 mL of HNO3 has been added f. pH when 50.0 mL of HNO3 has been added g....

  • Part A What is the pH at the equivalence point in the titration of 100.0 mL...

    Part A What is the pH at the equivalence point in the titration of 100.0 mL of 0.0500 M HOCI (K. = 3.5 x 10-) with 0.150 M NaOH? Express your answer to two decimal places. IVO AED ? pH = 5.0 Submit Previous Answers Request Answer X Incorrect; Try Again Provide Feedback Next >

  • Sketch a pH titration curve if 100.0 mL of 0.125 M NH3 solution is titrated with...

    Sketch a pH titration curve if 100.0 mL of 0.125 M NH3 solution is titrated with 0.15M HCl. Note the following three items on the curve. K, for NHa 1.8 x 105 pH= Calculate the starting pH (no HCl added) vol (mL)= Calculate the volume of HCl added to reach the equivalence point pH = Calculate the pH at the equivalence point.

  • Consider the titration of 100.0 mL of 0.100 M methylamine (CH3NH2) with 0.500 M HNO3. Calculate...

    Consider the titration of 100.0 mL of 0.100 M methylamine (CH3NH2) with 0.500 M HNO3. Calculate the pH at the following volumes of acid added. For CH3NH3+, pKa = 10.632 (a) Find the equivalence point volume. (b) 0 mL (c) 9.0 mL (d) 10.0 mL (e) 20.0 mL (f) 30.0 mL

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT