Question

please help with 2 and 3 asap thank you!

Colortul Heading 1 Normal Subtitle Selected Chemical and Physical Propotis of Fatty Aeld Condensod structural formula Molecular f ofCC melt lmono- or formula carbon double point C) point(C) poly- atoms bonds unsaturated? C122402 1244 C14H2802 14 C16H3202 16 CI8H3602 18 C20E14002 22 C22H4402 24 C24H4802 2 auric acid CH3(CH2) i OOOOH saturated 56 65 saturated 71 78 Saturated 83 Saturated 86 myristic Saturated 70 75 78 84 CHy(CH2)22COOH Mono -0.1 CH CH2) CH CHICH CI8H3402 18 C20H3802 20 Mono very low a-linolenic CH,ClH-(CH-CHCH2CI 130021 arachidonic CHy(CH24 CH-CHCH24(CH2)h000H C20H32020 Polyl 02 □ Focus MacBook Pro gondoic Mond Poly Poly Poly linoleic | CH3(CH2)4(CH-СНСТ CH,CH-CH CHCH,h(CH)OOH -5 very low a-linolenic arachidonie CHy(CH24(CH-CHCH24CH2OH C20H3220 204 CI8H3002 18 3 2. Now, look for trends in the data. Which fatty acids are solid at room temperature (about 25 C)? Which are liquid at room temperature? How does increasing the number of carbons in the hydrocarbon chain affect the melting point? Find a set of fatty acids in the table-as large a set as possible-that shows the trend in melting point with the number of carbons, without being complicated by any other variables. Make a graph to show this trend. What is the formula of the next fatty acid in the series? Use your graph to predict the melting point of this fatty acid. 3. The reason that longer chain molecules have higher boiling points is that longer chain molecules become wrapped around and enmeshed in each other much like the strands of spaghetti 4. How does increasing the number of double bonds in the hydrocarbon chain affect the melting point? Find a set of fatty acids in the table-as large a set as possible-that shows the trend in meltino noint with the number of double honds without heino icated huay ather Focus MacBook Pro

Answer 1

2) All saturated fatty acids with the number of carbons from C-12 to C-24 are solid at room temperature. And all unsaturated fatty acids are liquid at room temperature.

3) Fatty acids contain long hydrocarbon chain, this hydrocarbon chain is lipophilic in nature. This chain exhibits strong intermolecular van Der Waal forces of attraction. As the attraction between molecules is stronger it requires more energy to separate them thermodynamically. And hence melting point increases with the increase in the number of carbons in the fatty acids.

We will choose saturated fatty acids to show the trend:
X-axis: number of carbons
Y-axis: melting point

#ofC MP°C 12 90 Number of C's vs MP °C 54 63 70 75 16 80 20 70 y 3.214x 9 R2 0.966 0 24 84 50 12 13 14 15 30 10 12 16 18 No. of Cs 20 24 26

If we take the trend line (best-fit line) equation Y = 3.214*x + 9

where Y = mp, X = number of C's

Next fatty acid is: C24H52O2

To predict the mp of this fatty acid we can use the equation.

Substitute X = 24 and calculate Y = 3.214*24+9 = 86^oC

Thus the predicated MP of next fatty acid is 86^oC.