Question

2. For a given graph G, we say that H is a clique if H is a complete subgraph of Design an algorithm such that if given a gra

0 0
Add a comment Improve this question Transcribed image text
Answer #1

There are \binom{n}{k} different sub-graphs of k vertices of the graph G for a fixed k

We need to check for each ん2 possible edges between these k vertices whether such an edge exists or not. If it exists for each pair of vertices we have a clique and if it doesn't, we don't have a clique

For fixed k we have n(n O(n*) k!

So that our algorithm is a O(n*) 7l polynomial time algorithm which decides if a given undirected graph has a clique or not

Add a comment
Know the answer?
Add Answer to:
2. For a given graph G, we say that H is a clique if H is a complete subgraph of Design an algori...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 2. For a given graph G, we say that H is a clique if H is...

    2. For a given graph G, we say that H is a clique if H is a complete subgraph of Design an algorithm such that if given a graph G and an integer k as input, determines whether or not G has a clique with k vertices in polynomial time. (Hint: Try to first find a polynomial time algorithm for a different problem and reduce the clique problem to that problem).

  • 1) Consider the clique problem: given a graph G (V, E) and a positive integer k, determine whethe...

    1) Consider the clique problem: given a graph G (V, E) and a positive integer k, determine whether the graph contains a clique of size k, i.e., a set of k vertices S of V such that each pair of vertices of S are neighbours to each other. Design an exhaustive-search algorithm for this problem. Compute also the time complexity of your algorithm.

  • 4. Approximating Clique. The Maximum Clique problem is to compute a clique (i.e., a complete subgraph) of maximum size i...

    4. Approximating Clique. The Maximum Clique problem is to compute a clique (i.e., a complete subgraph) of maximum size in a given undirected graph G. Let G = (V,E) be an undirected graph. For any integer k ≥ 1, define G(k) to be the undirected graph (V (k), E(k)), where V (k) is the set of all ordered k-tuples of vertices from V , and E(k) is defined so that (v1,v2,...,vk) is adjacent to (w1,w2,...,wk) if and only if, for...

  • (a) Given a graph G = (V, E) and a number k (1 ≤ k ≤...

    (a) Given a graph G = (V, E) and a number k (1 ≤ k ≤ n), the CLIQUE problem asks us whether there is a set of k vertices in G that are all connected to one another. That is, each vertex in the ”clique” is connected to the other k − 1 vertices in the clique; this set of vertices is referred to as a ”k-clique.” Show that this problem is in class NP (verifiable in polynomial time)...

  • Show that the following three problems are polynomial reducible to each other Determine, for a given...

    Show that the following three problems are polynomial reducible to each other Determine, for a given graph G = <V, E> and a positive integer m ≤ |V |, whether G contains a clique of size m or more. (A clique of size k in a graph is its complete subgraph of k vertices.) Determine, for a given graph G = <V, E> and a positive integer m ≤ |V |, whether there is a vertex cover of size m...

  • Definition: Given a Graph \(\mathrm{G}=(\mathrm{V}, \mathrm{E})\), define the complement graph of \(\mathrm{G}, \overline{\boldsymbol{G}}\), to be \(\bar{G}=(\mathrm{V},...

    Definition: Given a Graph \(\mathrm{G}=(\mathrm{V}, \mathrm{E})\), define the complement graph of \(\mathrm{G}, \overline{\boldsymbol{G}}\), to be \(\bar{G}=(\mathrm{V}, E)\) where \(E\) is the complement set of edges. That is \((\mathrm{v}, \mathrm{w})\) is in \(E\) if and only if \((\mathrm{v}, \mathrm{w}) \notin \mathrm{E}\) Theorem: Given \(\mathrm{G}\), the complement graph of \(\mathrm{G}, \bar{G}\) can be constructed in polynomial time. Proof: To construct \(G\), construct a copy of \(\mathrm{V}\) (linear time) and then construct \(E\) by a) constructing all possible edges of between vertices in...

  • Problem . Given the formula f- construct a graph G such that f is satisfiable iff G has a clique ...

    Design & Analysis of Algorithms Problem . Given the formula f- construct a graph G such that f is satisfiable iff G has a clique of size 3. . Problem . Given the formula f- construct a graph G such that f is satisfiable iff G has a clique of size 3. .

  • Professor Amongus has just designed an algorithm that can take any graph G with n vertices and de...

    Professor Amongus has just designed an algorithm that can take any graph G with n vertices and determine in O(n^k) time whether G contains a clique of size k. Does Professor Amongus deserve the Turing Award for having just shown that P = NP? Why or why not? R-17.12 Professor Amongus has just designed an algorithm that can take any graph G with n vertices and determine in O(nk) time whether G contains a clique of size k. Does Professor...

  • The input to SPANNINGTREEWITHKLEAVES is a graph G and an integer K. The question asked by...

    The input to SPANNINGTREEWITHKLEAVES is a graph G and an integer K. The question asked by SPAN NINGTREEWITHKLEAVES is whether G has a spanning tree with exactly K leaves. Problem 3. Show that SPANNINGTREEWITIIKLEAVES is NP-complete. Hint: There is a simple polynomial time reduction from HAMILTONIANPATH to SPANNINGTREEWITHKLEAVES.

  • 2. Consider the following problem: Input: graph G, integer k Question: is it possible to partition...

    2. Consider the following problem: Input: graph G, integer k Question: is it possible to partition vertices of G into k disjoint independent sets? Is this problem polynomial or NP-complete? Explain your answer

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT