Question

Samples of three gases, N20 (g), Kr (g) and N2 (g) at STP are placed in three 1.00 L containers. The same amount of heat is added to all three samples. Match the final temperatures of the samples with the proper gas Kr: 293.48 K N2: 287.64 K N20: 283.52 K You are correct. Previous Tries Your receipt no. is 156-2913 Match the molar heat capacities with the proper gas. N20: 40.5 J/mol K N2: 29.1 l/mol K Kr: 20.8 J/mol K You are correct. Previous Tries Your receipt no. is 156-3271 Based on this information, determine how much heat was added to the systems. Submit Answer Tries 0/99

Answer 1

The formula Q = n x C x ∆T represents the heat q required to bring about a ∆T difference in temperature of one mole of any matter. The constant C here is called the molar heat capacity of the body.

Q_Total = Q_Kr + Q_N2 + Q_N2O

Q_Total = (n_Kr x C_Kr x ∆T_Kr ) + ( n_N2 x C_N2 x ∆T_N2 ) + ( n_N2O x C_N2O x ∆T_N2O )

Q_Total = ( 1 x 20.8 J/mol K x 293.48 K ) + ( 1 x 29.1 J/mol K x 287.64 K ) + ( 1 x 40.5 J/mol K x 283.52 K )

Q_Total = 6104.38 J + 8370.32 J + 11482.56 J

Q_Total = 28957.26 J

Q_Total = 25.96 KJ