Question

Gaseous fuel has the following volumetric composition CH4 0.38, H2 0.26 , N2 0.06 CO 0.26, CO2 0....

Gaseous fuel has the following volumetric composition CH4 0.38, H2 0.26 , N2 0.06 CO 0.26, CO2 0.04. Find Stoichiometric air/fuel ratio by volume and the corresponding wet and dry volumetric analyses of the products of combustion

0 0
Add a comment Improve this question Transcribed image text
Answer #1

No lumeHC composlHon CO0 0 26 For completeombuston of each element 2. mofe of 02 2 026 o 13 mole of o 2t mole of H20 CO を02 → co2 t mote of o mole of o2 2CH4 2 mole of 02- I mole of CO2- -2420 2mole of H20 Cornbu sHon 0.13 t o.13ナ0.76 1.o2 mole of 2 Anrb) mote/moleof fuet ome N0(yme . 6152 -o62 0 28 H20 (5, 421、 0 0.13ナ 0-131 o、76 18.22小 0 2 6962./.

Add a comment
Know the answer?
Add Answer to:
Gaseous fuel has the following volumetric composition CH4 0.38, H2 0.26 , N2 0.06 CO 0.26, CO2 0....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A natural gas fuel consists of the following volumetric composition: Methane, CH4: 92.5 % Ethane, C2H6:...

    A natural gas fuel consists of the following volumetric composition: Methane, CH4: 92.5 % Ethane, C2H6: 3.7 % Propane, C3H8: 0.8 % Nitrogen, N2: 3 % (a) Write out the complete combustion equations for all the combustible constituents individually. (b) Calculate the stoichiometric air to fuel (A/F) ratio on a volume basis. (c) Determine the wet volumetric analysis of the combustion products. (d) Find the dry volumetric analysis of the combustion products.

  • Problem 4 A fuel gas has a composition by volume of: 50% H2 , 6% CO2,...

    Problem 4 A fuel gas has a composition by volume of: 50% H2 , 6% CO2, 4% N2 , 40% CO. The dry exhaust gas analysis (% by volume) of the actual combustion process indicates 9.2% CO2, 0% CO, some O2. Recall that for gases, volumetric composition is the same as molar composition. (a) What air/gas ratio (by volume) is required for stoichiometric combustion? (m? air/ m² fuel gas) (b) What air/gas ratio (by volume) has actually been used? (m’...

  • H.W.6.17. A boiler is supplied with coal gas of the following composition: 53.6% H2, 9% CO,...

    H.W.6.17. A boiler is supplied with coal gas of the following composition: 53.6% H2, 9% CO, 25% CH4, 3% C4H8, 0.4% O2, 3% CO2, 6% N2. If the air fuel ratio is 6.5/1 by volume, calculate the analysis of the dry products of combustion by volume.

  • Thermodynamics 6. A certain natural gas has the following volumetric analysis: 65 percent CH4, 8 percent...

    Thermodynamics 6. A certain natural gas has the following volumetric analysis: 65 percent CH4, 8 percent H2, 18 percent N2, 3 percent O2, and 6 percent CO2. This gas is now burned completely with the stoichiometric amount of dry air. What is the air-fuel ratio for this combustion process, and the equivalence ratio?

  • 1. A gaseous fuel has the following volumetric analysis: CH4-60%, C2H6-30%, H,-10% The fuel (at 1...

    1. A gaseous fuel has the following volumetric analysis: CH4-60%, C2H6-30%, H,-10% The fuel (at 1 tm, 25°C) is burnt with stoichiometric air at 1 atm, 25°C, The products are at 150°C. Determine the A/F ratio, the heat released per kg of fuel and the dew point of the products. (12)

  • A mixture of gas has the following volumetric analysis 0.29 CO, 0.12 H2 , 0.03 CH4...

    A mixture of gas has the following volumetric analysis 0.29 CO, 0.12 H2 , 0.03 CH4 , 0.04 CO2 ,0.52 N2, Calculate the values of Cp, Cv in kJ/mole K. The values of Cp for the constituents are: for CO, Cp=35.8kJ/mole K, for H2 ,Cp=28.89kJ/mole K, for CH4, Cp=35.8kJ/mole K, for CO2 ,Cp =37.22 kJ/mole K , for N2 , Cp=29.14kJ/mole K

  • A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of...

    A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.

  • A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of...

    A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.

  • Please provide step by step annotated solution for the question above, we are given the following...

    Please provide step by step annotated solution for the question above, we are given the following numerical answers to work towards: A/F by mass = 12.14; Wet analysis: CO2=6.15%, H2O=3.16%,CO =10.64% and N2=80.04% 6. Determine the Air/Fuel ratio by mass for a fuel approximating to hexane CsH14 when only 80% of the air required for stoichiometric combustion is provided. Also perform wet volumetric analysis on the combustion products at temperature of 25 °C and pressure of 1 bar. [20 marks]

  • The product gas from a liquid fuel (C_6 H_x) combustion reaction has the following dry-basis molar...

    The product gas from a liquid fuel (C_6 H_x) combustion reaction has the following dry-basis molar composition: 12.97% CO_2, 1.44% CO, 4.32% O_2, and 81.27% N_2. Assume no solid or liquid products! Liquid fuel disappears completely. calculate the Ratio of carbon and hydrogen.  What is x?? (C_6 H_x) what is %(percent Excess Air)?????? and Excess air?? Please explain in detail.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT