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what is the unknown compound given the IR and H NMR
2.35 2 12 10 PTSId: 4096
06 S8 08 SL OL S9 09 009 L 00SS 8 8 8 ωω して乙乙ヤ切0, g 9 0610 1686 18 8
2.35 2 12 10 PTSId: 4096
06 S8 08 SL OL S9 09 009 L 00SS 8 8 8 ωω して乙乙ヤ切0, g 9 0610 1686 18 8
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Answer #1

Ans: benzamide since in

IR: stretching 3433 n 3326cm-1 denote amide banding frequency

With c=o stretching at 1614cm-1

Stretching above 3000cm-1 showing aromaticity of compound

NMR : signals between 6-8 ppm corresponds to hydrogen of aromatic rings

Aromatic N-H group shows signal between 3.0-5.0ppm shown in figure above .these hydrogen are deshielded due to anisotropy of the ring and the resonance that removes electron density from nitrogen and change its hybridization

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