Question

PROBLEMA 2. Calcule la fuerza normal en A en el sistema de barra y poleas que se muestra. En O hay un pin". Asuma que la superficie en A es lisa o suave. El valor de masa del cilindro (m1) es igual a 20 kg. Evalúe la fuerza normal en A para valores de mi (masa del cilindro) de 10kg hasta 60 kg en intervalos de 10 (6 casos). Haga una grafica de Normal vs masa del cilindro (Normal en y / Masa en x). Se recomienda que utilice una hoja de cálculos de algún programa (ejemplo Excel) y que saque la ecuación de la normal en función de m Comente acerca de los resultados, ¿en qué punto el sistema se vuelve inestable (se cae la barra )? В 30° 30° 3 2L Im

Calculate the normal force in A in the bar and pulley system shown. In O there is a "pin". Assume that the surface at A is smooth or smooth. The mass value of the cylinder (m1) is equal to 20 kg. Evaluate the normal force at A for values of m1 (cylinder mass) from 10kg to 60kg at intervals of 10 (6 cases). Make a graph of Normal vs. cylinder mass (Normal in y / Mass in x). It is recommended that you use a spreadsheet of some program (Excel example) and that you extract the equation from the normal one based on m1.

Comment on the results, at which point the system becomes unstable (the bar falls off)

Answer 1

Sr. No	Mass of Bar (m)	Mass of cylinder (m1)	Force due to mass of bar	Force due to cylinder mass	Tension in the string	String tension in X direction	String tension in Y direction	Moment due to string tension in X direction	Moment due to string tension in Y direction	Moment due to weight of the bar	Normal force at point A
1	20	10	196.2	98.1	49.05	42.47856	24.52498	14.15951	14.15951	84.95711	56.6381
2	20	20	196.2	196.2	98.1	84.95711	49.04996	28.31902	28.31902	84.95711	28.31908
3	20	30	196.2	294.3	147.15	127.4357	73.57494	42.47852	42.47852	84.95711	6.51E-05
4	20	40	196.2	392.4	196.2	169.9142	98.09992	56.63803	56.63803	84.95711	-28.319
5	20	50	196.2	490.5	245.25	212.3928	122.6249	70.79754	70.79754	84.95711	-56.638
6	20	60	196.2	588.6	294.3	254.8713	147.1499	84.95705	84.95705	84.95711	-84.957
The bar falls of at point when Reaction force becomes negative means the force direction changes. I have assumed mass of bar as 20 kg.

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