
(The measured data were at temperature near room temperature.)
For monatomic molecules, f=3 (translational kinetic energy degrees of freedom)
so we can get Cv/R=f/2=1.5, Cp/R= (f+2)/2=2.5, r=(f+2)/2=1.67
The results agree with the experimental observation.
For monatomic molecules, f=7
we can get Cv/R=f/2=3.5, Cp/R= (f+2)/2=4.5, r=(f+2)/2=1.286
The results disagree with the experimental observation.
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I think that some energy modes (degree of freedom) were not fully excited at room temperature, if the temperature is high enough, the experimental value will getting closed
to theoretical value?
and what parameter will effect the value in different temperature?
Thanks!
The answer of the question is given on the fallowing page


(The measured data were at temperature near room temperature.) For monatomic molecules, f=3 (tran...
The measured data were at temperatures near room
temperature.
For diatomic molecules, I know how to calculate the value of r,
Cp/R, Cv/R, (Cp-Cv)/R.
I confused why value of Cl2 has a gap with others diatomic
molecules value (r, Cp/R, Cv/R, (Cp-Cv)/R) in experimental.
Thanks!
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Are there any information need to give you?
TABLE 3-3 Gas He Ne 1.659 2.521.519 1.001 1.64 1.67 1.68 1.66 2.52 1.5091.008 Kr Xe 1.4103.422.438 0.9995 1.401 3.522.504 1.004 1.404 3.502.448 1.005 1.4043.502.488 1.005...
Suppose 1000 coins are tossed. Use the normal curve approximation to the binomial distribution to find the probability of getting the following result. Exactly 495 heads Use the table of areas under the standard normal curve given below. Click here to view page 1. Click here to view page 2. Click here to view page 3. Click here to view page 4. Click here to view page 5. Click here to view page 6. The probability of getting exactly 495...
Suppose 16 coins are tossed. Use the normal curve approximation to the binomial distribution to find the probability of getting the following result. More than 11 tails. Use the table of areas under the standard normal curve given below. Click here to view page 1. Click here to view page 2. Click here to view page 3. Click here to view page 4. Click here to view page 5. Click here to view page 6. Binomial probability = (Round to...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...
I ONLY NEED HELP WITH PART OF PART "B"
I've figured out the test statistic is -1.73 and the degrees of
freedom are 5. However, I'm having a hard time finding the P value
via the chart (which I'm required to learn how to do).I think the
chart immediately bellow this is the one used to find the p-value.
However, I know at least one (or more) of the charts bellow is
what's used. Please let me know which chart...
I ONLY NEED HELP WITH PART OF PART "B"
I've figured out the test statistic is -1.73 and the degrees of
freedom are 5. However, I'm having a hard time finding the P value
via the chart (which I'm required to learn how to do).I think the
chart immediately bellow this is the one used to find the p-value.
However, I know at least one (or more) of the charts bellow is
what's used. Please let me know which chart...