a) in a complementation test mutants which shows the same phenotype is crossed, this is to identify the number of genes involved to produce normal phenotype and the number of alleles of each gene.
b) if 2 mutants are can complement the phenotype that is the in the hybrid shows wildtype phenotype then the 2 mutations are in 2 different genes if 2 mutants cannot complement the phenotype means, 2 mutations are in the same gene, so the hybrid lacks one gene in the pathway.
so here
1,7-A
2,12-B
3,6-C
4,8,11-D
5,10-E
9-F
are different complementation groups, so there are 6 genes involved in the pathway, A, B, C, D, E, F.
and 1,7 are alleles of A
2,12 are alleles of B
3,6 are alleles of C
4,8,11 are alleles of D
5,10 are alleles of E
9 is the only allele of gene F
2. To understand the genetic basis of locomotion in the diploid nematode Caenorhabditis elegans, ...
The recessive dumpy, dpy, mutants of the nematode worm Caenorhabditis elegans have a compact body; the recessive uncoordinated, unc, mutants have defective movement coordination. When a dumpy, uncoordinated hermaphrodite (XX) is mated with a normal male (XO), the F1 male progeny all are uncoordinated and the hermaphrodites are not, but neither the males nor the hermaphrodites are dumpy. (Note: Hermaphrodites will out-cross preferentially to self-crossing.) A. Are these genes sex-linked or autosomal? Explain for each. Use proper gene and allele...
3. (2 points) In the nematode roundworm, Caenorhabditis elegans, the LIN-14 protein controls the timing of certain cell divisions during development. LIN-14 protein levels are normally high in early development but decrease in the later stages. In a lin-4 mutant, the level of LIN-14 protein stays high throughout development, changing the pattern of cell divisions in the animal and producing defects in the shape of the animal. The lin-4 gene encodes a microRNA that binds to a sequence in the...