



please answer all fill in the blank
Test statistic
F = MS(between) / MS(Within) = 662.70/153.63 = 4.31
Fcritical at α = 0.05 is F.INV.RT(0.05, 1, 28) = 4.196
At a significance level of α = 0.05, the null hypothesis is rejected. You find that you can conclude that the direction that the stroller faces influences a child's expressive vocabulary at 18 months.
t test statistic:
df = 15+15-2 =28
the critical t score = T.INV.2T(0.05, 28) = +2.048, -2.048
At a significance level of α = 0.05, the null hypothesis is rejected. You find that you can conclude that the direction that the stroller faces influences a child's expressive vocabulary at 18 months.
When you evaluated the mean difference from the independent-measures study comparing only two samples, the ANOVA and t test resulted in same conclusion.
Keep the Highest: Attempts: /4.5 7. Comparing ANOVA and the t test for an independent-measures hy...
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