Question

8. (6 pts) E. coli is a facultative anaerobe. Using the data in the table below, answer the following questions: a. What type of experiment or technique was used b. What is the doubling time in each growth c. What is the reason for the difference in doubling to calculate CFU/ml? condition? time? Terminal electron acceptor CFU/ml at time 0 CFU/ml at time 8 hrs O2 1.25 x 102 1.25 x 102 7.5 x 108 3.1 x 106 NO3

Answer 1

A. Facultative anaerobes are able to adapt their metabolism and can grow under conditions with or without oxygen but prefer aerobic conditions.
So, microorganisms are cultured, either the culture vessel is shaken to aerate the medium or sterile air is pumped. CFU/ml calculated from microscope count.

B.

NO5 13) po-ns g은0-301 C8_o) = 2.398 = 2.408 6 44-2 02 24082 8.26.18 NDa 8