Question

I cannot figure out how to do number four. Can someone please show me step by step how to do it?

This project is made up of 4 different parts. The dataset for all 4 parts is given in the Students are encoruraged to use software (Mimitab, excel tc) to complete the help see your professor. CARS: A sample of 20 cars, including measurements of fuel consumption (eity mi/gal and highway mi/gal), weiglit (poumds), mumber of eylinders, engine disp gases emitted (in tons/year), and amount of tailpipe emissions of NO. (in lb/yT). HW WEIGH CYLINDE DISPLACEME MAN CAR Chev. Camaro Chev. Cavalier Dodge Neon Ford Taurus Honda Accord Lincoln Cont. Mercury Mystique 20 29 3115 6 Mitsubishi Eclipse 22 33 32354 GH NO AUTO G 19 30 3545 6 23 31 2795 23 32 2600 4 19 27 3515 6 23 30 3245 4 17 24 3930 8 3.8 12 4 10 1 101 12 1 25 14 1 34. 4.6 2.5 12 4 10 34 Olds. Aurora Pontiac Grand Am22 30 3115 4 Toyota Camry Cadillac DeVille17 26 4020 8 Chev. Corvette 17 26 3995 13 4 25. 23 32 3240 4 10 1 34. 4.6 5.7 2.5 13 4 34 12 25. 12 1 34. 12 4 34 18 28 3220 8 Chrysler Sebring 19 27 31756 Ford Mustang 20 29 34506 19 27 3225 6 17 24 3985 8 32 37 2440 12 4 BMW 3-Series Ford Crown Victoria 25. 14 1 25 4.6 1.6 1.6 Honda Civic Mazda Protege 9 25. 29 34 2500 4. Is there evidence that automatic cars are more common than manual cars? i. Use a 0.05 significance level to conduct a suitable hypotheses test using the dataset MAN/AUTO as a sample to conduct your test. Set hypotheses, find your point estimate, determine the sampling distribution, find the test statistic, find the p-value and conclude the test. ii.

Answer 1

p is the proportion of Automatic cars
here n = sample size = 20
X = number of Automatic cars = 14

(1) Null and Alternative Hypothese The following null and alternative hypotheses need to be tested: Ho p 0.5 Ha p0.5 This corresponds to a right-tailed test, for which a z-test for one population proportion needs to be used (2) Rejection Region Based on the information provided, the significance level is α 0.05, and the critical value for a right-tailed test is zc1.64 The rejection region for this right-tailed test is R 1.64 Test Statistics The z-statistic is computed as follows 0.7 0.5 p po - 1.789 Vpo (1 P)/n /0.5(1 - 0.5)/20 (4) Decision about the null hypothesis Since it is observed that z 1.789 ze1.64, it is then concluded that the null hypothesis is rejected Using the P-value approach: The p-value is p 0.0368, and since p 0.0368 < 0.05, it is concluded that the null hypothesis is rejected (5) Conclusion It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim 0.05 significance level that the population proportion p is greater than po, at the α