
a) The most appropriate response variable will be Annual Net Sales/$1000, rest of the variables will be predictors.
b) The fitted model estimated using MANITAB is given below
X1 = - 18.9 + 16.2 X2 + 0.175 X3 + 11.5 X4 + 13.6 X5 - 5.31 X6.
c) We will set up the null hypothesis that.
;
i= 1,2,3,4,5,6. or all regression coefficient are equal to
zero.
; at least one regression coefficient is not equal to
zero.
The overall significance of the model is used with F.Test and the Anova Table is given below
| Source | DF | SS | MS | F | P.Value |
| Regression | 5 | 952539 | 190508 | 611.59 | 0.000 |
| Residual Error | 21 | 6541 | 311 | ||
| Total | 26 | 959080 |
Since calculated P.value =0.000 which is less then 0.05. Hence we will accept our null hypothesis and concludes that at least one regression coefficient is not equal to zero.
d) We will set up the null hypothesis that.
To check the individual regression coefficient is whether equal to zero or not. We use t.test.
| Predictor | Coef | SE Coef | T | P.Value |
| Constant | -18.86 | 30.15 | -0.63 | 0.538 |
| X2 | 16.202 | 3.544 | 4.57 | 0.000 |
| X3 | 0.17464 | 0.05761 | 3.03 | 0.006 |
| X4 | 11.526 | 2.532 | 4.55 | 0.000 |
| X5 | 13.58 | 1.77 | 7.67 | 0.000 |
| X6 | -5.311 | 1.705 | -3.11 | 0.005 |
Since P.Value for Constant term is 0.538 which is greater then 0.05. hence we will accept our null hypothesis and concludes that constant term is not significant.
It is not significant because calculated P.Value is much greater then 0.05 (significance level).
e) The estimated value of error variance = 311.
f) Since R-Sq = 99.3%. Which means that 99.3% of response variance is explained by the model.
3. Description of each X and data for 27 franchise stores are given below The data (X1, X2, X3, X4, X5, X6) are for each franchise store. X1 annual net sales/$1000 X2 number sq. ft/1000 X3 - inv...
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