Question

9. Pressure at Mt. Everest If we rearrange the ideal gas law to be in terms of density: pR and also consider the affects of the buoyancy force: apE, we can combine these equations to find the atmospheric pressure as a function of height above the ground. Do so to find the air pressure at an elevation of 8838 meters, close to the peak of Mt. Everest. You can assume that g is constant all the way up and so is the temperature (273 K)-neither of which is true, but it would be hard to do this if we didn't assume that. (The molar mass, M, of air is 28.8x 10-3 kg/mol and the gas constant, R is 8.314 J/(mol K). Hint: you'll need to do some integratin') PM atm Submit Answer

Answer 1

PM RCT RT RT Ho y RT -28. 8x 9.8 8838