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If we rearrange the ideal gas law to be in terms of density: ρ=PM/RT and also...

If we rearrange the ideal gas law to be in terms of density: ρ=PM/RT and also consider the affects of the buoyancy force: dP/dy=−ρg, we can combine these equations to find the atmospheric pressure as a function of height above the ground. Do so to find the air pressure at an elevation of 8838 meters, close to the peak of Mt. Everest. You can assume that g is constant all the way up and so is the temperature (273 K) - neither of which is true, but it would be hard to do this if we didn't assume that. (The molar mass, M, of air is 28.8×10^-3 kg/mol and the gas constant, R is 8.314 J/(mol K). Hint: you'll need to do some integration'.) -----atm

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