Consider the following mechanism:
H2S <--> H+ + HS- (fast equilibrium)
Cl2 + HS --> 2Cl- + H+ + S (slow)
An intermediate is
And the best rate law is
Consider the following mechanism: H2S <--> H+ + HS- (fast equilibrium) Cl2 + HS --> 2Cl- + H+ + S (slow) An intermediate is And the best rate law is
consider the aqueous reaction of Cl2 + H2S -> S + 2HCL . It may happen by the following mechanism 1: Cl2-> <- 2Cl fast 2: Cl+H2S -> <- HCl + HS fast 3: HS +Cl --> --< HCl + S slow DERIVE a rate law for overall reaction using the given mechanism and rate determining step without using intermediates in the rate law.
The proposed mechanism for a reaction is Cl2 => Cl+ + Cl- Slow Cl- + H2S => HCl + HS- Fast Cl+ + HS- => HCl + S Fast Which of the following would be a rate law for the reaction? A. rate = k[Cl2] B. rate = k[Cl2][H2S] C. rate = k[Cl2]1/2[H2S] D. rate = k[Cl-][H2S] E. rate = [Cl+][Cl-]
Consider the following three step mechanism for a reaction Cl2 > 2Cl Fast Cl+CHCl3 > HCl+CCl3 Slow Cl+CCl3 > CCl4 Fast What is the predicted rate law? How do you do it? The answer is rate=K[Cl2]^.5 [CHCl3]
1. Consider the reaction, Cl2 + H2S => 2 HCl + S, which is found to be half order in Cl2 and first order in hydrogen sulfide. Which step of the proposed mechanism must be slow in order to agree with this rate law? Cl2 => 2 Cl Cl + H2S => HCl + HS Cl + HS => HCl + S 2. Consider the reaction, H2 + I2 => 2 HI , which is found to be first order...
3.(12pts) The reaction Cl(aq) + HS(a) determined DRL S)+(aq) +2 Cl(aq) has the experimentally rate k[Cl2][H2S] Which of the following mechanisms is(are) consistent with the experimental results. Mech I Mech 11, Mech III Cl2 +H2S >H CI CI+HS (slow) CI+ + HS. …>H+ + Cl. + S H2S = HS. + H+ HSCl2 2CI +S+H (fast) (fast equil) (slow) H2S HS+H (fast equil) (fast equil) (slow) 4. (10 pts) Write the equilibrium constant Ke expression for the following 4 KO:(s)...
1. The rate of formation of carbon tetrachloride from chloroform, CHCl3(g) + Cl2(g) => CCl4(g) + HCl(g) is first order in CHCl3 and half order in Cl2. Which step of the proposed mechanism must be slow in order to agree with this rate law? 1. Cl2(g) => 2 Cl(g) 2. Cl(g) + CHCl3(g) => HCl(g) + CCl3(g) 3. CCl3(g) + Cl(g) => CCl4(g) 1. 1 2. 2 3. 3 2. The proposed mechanism for a reaction is Cl2 =>...
Consider the following mechanism: A2B (rapid equilibrium) B + 2C + E (slow) E F (fast) Which one of the following experimentally determined rate laws is consistent with this reaction mechanism? Multiple Choice Rate = KALC2 O Rate = KAVB2 O Rate = K[AIC] O Rate = MBIC2 Rate = ka]1/2012 O
Given the two reactions H2S⇌HS−+H+, K1 = 9.87×10−8, and HS−⇌S2−+H+, K2 = 1.40×10−19, what is the equilibrium constant Kfinal for the following reaction? S2−+2H+⇌H2S Given the two reactions PbCl2⇌Pb2++2Cl−, K3 = 1.82×10−10, and AgCl⇌Ag++Cl−, K4 = 1.16×10−4, what is the equilibrium constant Kfinal for the following reaction? PbCl2+2Ag+⇌2AgCl+Pb2+
Consider the reaction 2 NO + Cl2 → 2 NOCI A possible mechanism is: Cl2 ⇄ 2 Cl (fast) Cl + NO → NOCl (slow) If this is correct, the rate law will be: A. rate = k [NO]0.5[Cl] B. rate = k [NO]2[Cl2] C. rate = k [NO][Cl2] D. rate = k [NO][Cl]2 E. rate = k [NO][Cl2]0.5
Part A= Given the two reactions H2S⇌HS−+H+, K1 = 9.42×10−8, and HS−⇌S2−+H+, K2 = 1.32×10−19, what is the equilibrium constant K final for the following reaction? S2−+2H+⇌H2S Part B= Given the two reactions PbCl2⇌Pb2++2Cl−, K3 = 1.89×10−10, and AgCl⇌Ag++Cl−, K4 = 1.23×10−4, what is the equilibrium constant K final for the following reaction? PbCl2+2Ag+⇌2AgCl+Pb2+