Question

Complete the mult() and printArr() functions

#include <iostream> using namespace std; void init(int arr]05], int x)t //initialization loop for row 1 and 2 for(int i = 0; i < 2; i++){ arr i][j] x; void mult(int arr JSD //multiply the elements of row 2 by row 1, and store result in row3 void printArr int arr ][5]) // a loop to print out all the elements of the array int main) int arr[3105]

Answer 1

C++ code

============================================================================================

#include<iostream>

using namespace std;

void init(int arr[][5],int x)
{
  
   for(int i=0;i<2;i++)
   {
       for(int j=0;j<5;j++)
       {
               arr[i][j]=x;
       }
       ++x;
   }
  
}

void mult(int arr[][5])
{
   //multiply row 2 by row 1
   for(int i=0;i<5;i++)
   {
       arr[2][i]=arr[0][i]*arr[1][i];
   }
  
  
}
void printArr(int arr[][5])
{
   //loop to print elements of the array
   for(int i=0;i<3;i++)
   {
       for(int j=0;j<5;j++)
       {
           cout<<arr[i][j]<<" ";
      
       }
       cout<<endl;
   }
}

int main()
{

int arr[3][5];
int x;

cin>>x;
init(arr,x);
mult(arr);

printArr(arr);
return 0;
}

============================================================================================

Output

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