Question

Write loop(s) that print ALL the content of the following 2D array

#include <iostream>

using namespace std;

int main(){
  
int rows;
int cols;
int offset;
cin >> rows;
cin >> cols;
cin >> offset;
  
int** arr = new int*[rows];
for(int i = 0; i < rows; ++i)
arr[i] = new int[cols];
  
for(int i = 0; i < rows; i++) // initialization
for(int j = 0; j < cols; j++)
arr[i][j] = offset + i;
  
// printing, your code goes here
  
return 0;
}

Answer 1

#include <iostream>
using namespace std;

int main()
{

int rows;
int cols;
int offset;
cin >> rows;
cin >> cols;
cin >> offset;

int** arr = new int*[rows];
for(int i = 0; i < rows; ++i)
arr[i] = new int[cols];

for(int i = 0; i < rows; i++) // initialization
for(int j = 0; j < cols; j++)
arr[i][j] = offset + i;

//Print the contents of array
for(int i = 0; i < rows; i++)
{
for(int j = 0; j < cols; j++)
{
      cout<<arr[i][j]<<"\t";
}
    cout<<endl;
}

return 0;
}

Output

n no