Can someone explain how the answer is 2. thanks 0.2/0.2 pts Question 2 Read the program and the descriptions below #include <stdio.h> int x=0x10, y=0x200, z=0x30; int main) int a, b-0x12, c-0x20...

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0.2/0.2 pts Question 2 Read the program and the descriptions below #include <stdio.h> int x=0x10, y=0x200, z=0x30; int main) Can someone explain how the answer is 2. thanks

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Answer 1

Answer #1

Since x,y and z are the global variables these are stored in the Data Segment of the Ram compared to the local variables which are stored in the heap.Since the execution of the code is generally from the LHS to the RHS.

Creation of z happens after x and y.Therefore if we are referring z variable memory manager has to jump 2 steps to access z.Therefore the offset associated with the z variable will be 2.

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Can someone explain how the answer is 2. thanks 0.2/0.2 pts Question 2 Read the program and the descriptions below #include <stdio.h> int x=0x10, y=0x200, z=0x30; int main) int a, b-0x12, c-0x20...

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Add Answer to: Can someone explain how the answer is 2. thanks 0.2/0.2 pts Question 2 Read the program and the descriptions below #include <stdio.h> int x=0x10, y=0x200, z=0x30; int main) int a, b-0x12, c-0x20...

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Can someone explain how the answer is 2. thanks 0.2/0.2 pts Question 2 Read the program and the descriptions below #include <stdio.h> int x=0x10, y=0x200, z=0x30; int main) int a, b-0x12, c-0x20...