Question

1. (1, a, b, c)

please answer and explain all abc using information below:

Read the program and the descriptions below before answering the next 6 questions. #include <stdio.h> int w = -1, x = 3, y = -5, z = 7; int main() { = 4, b = 3, c = 2, d = 1; while (b >= -2) { b = b + W; y = z - d; int a } printf("b = %d y = %d\n", b, y); } Assume that (1) rg represents the register pointing to the beginning of the locations where the global variables are stored, (ii) rL denotes the register that records the start of the locations where the local variables are stored, and (iii) the offsets of the variables in the program above are given in the table below. In the table, each capital letter represents an integer. Variable Offset a A b B с с d ২| 2 W х X у Y Z N

1. a, b, c

Answer 1

Here is the solution to above problem . PLEASE GIVE A THUMBS UP!!!!

1) The offset value of A is 0 because it is the first variable in local space

2) The offset value of X is 2 because the size of int is 2 byte and from starting address we need to move two byte forward to get x

3) The Register 6 is the register which points to the top of the stack in LC-3 machine