Required Code Screenshots:
![Create an empty dictionary and associate it with the #name d3 d3 For every (a, b) present #in the dictionary dl. for (a,b) in d1.items): Check if there is a value (b, c) #in the dictionary d2 or not. if b in d2: #If there is a value (b, c) #in the dictionary d2 then, add (a, c) to the #dictionary d3. d3 ad2 [b]](http://img.homeworklib.com/questions/d1e05d80-03a8-11ea-b879-ef8231516276.png?x-oss-process=image/resize,w_560)
Required Code To Copy:
#Create an empty dictionary
#and associate it with the
#name d3.
d3 = {}
#For every (a, b) present
#in the dictionary d1.
for (a,b) in d1.items():
#Check if there is a value (b, c)
#in the dictionary d2 or not.
if b in d2:
#If there is a value (b, c)
#in the dictionary d2 then,
#add (a, c) to the
#dictionary d3.
d3[a] = d2[b]
Complete Code Screenshots (To check the execution of the above given code):

Sample Output:

Code To Copy:
d1 = {2:3, 8:19, 6:4, 5:12}
d2 = {2:5, 4:3, 3:9}
#Create an empty dictionary
#and associate it with the
#name d3.
d3 = {}
#For every (a, b) present
#in the dictionary d1.
for (a,b) in d1.items():
#Check if there is a value (b, c)
#in the dictionary d2 or not.
if b in d2:
#If there is a value (b, c)
#in the dictionary d2 then,
#add (a, c) to the
#dictionary d3.
d3[a] = d2[b]
#Display the
#dictionary d3.
print(d3)
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