2. If lung problems like emphysema occur, how it is affected the blood pH of the patient? Explain in detail. 3. 25.0 mL of 0.212 M NaOH is neutralized by 13.6 mL of an HCl solution. What is the molarity (M) of the HCl solution? State the given and needed quantities, state equalities and conversion factors, also the cancellation.
Balanced chemical equation is:
NaOH + HCl ---> NaCl + H2O
Here:
M(NaOH)=0.212 M
V(NaOH)=25.0 mL
V(HCl)=13.6 mL
According to balanced reaction:
1*number of mol of NaOH =1*number of mol of HCl
1*M(NaOH)*V(NaOH) =1*M(HCl)*V(HCl)
1*0.212*25.0 = 1*M(HCl)*13.6
M(HCl) = 0.3897 M
Answer: 0.390 M
2. If lung problems like emphysema occur, how it is affected the blood pH of the patient? Explain in detail. 3. 25.0 mL...
11. How many mL of a 0.525 M NaOH solution is needed to neutralize 15.00 mL of a 1.25 M H2SO4 solution? 12. What is the molarity of an HCl solution if 25.0 mL of 0.212 M NaOH is used to neutralize 13.6 mL of the HCI solution? 13. If 10.0 mL of 0.121 M H2SO4 is neutralized by 17.1 mL of KOH solution, what is the molarity of the KOH solution?