Question

chemm

1. Your boss asks you to prepare and then standardize a sodium hydroxide solution, which do as you did in this lab. The average concentration is 0.1063M. He then hands you of nitrie acid and asks you to titrate it with your NaOH solution. It requires 27.33mL of you standardized NaOH Nolution to titrate 24.79mL of the nitric acid solution. Write a chemical equation for the neutralization reaction and then calculate the molarity of the nitric acid solu HNO3+ NaOH → NaNO3 + H2O Molarity of sodium hydroacide a blume of sodium hydroxide Molality of nitric acid & Volume of nithe cold 0.1066 x 27.33, ? * 24.79 7= 0.1063 y 27, 33/24.74= 0.1172M

Answer 1

ULUS) HNO3 + NaOH - NaNg +HO Suppose Molarity of HNO solution be 'M, Volume of HHO solution = v = a 4.79mL. Given Concentration of NaOH = M = 0.1063M Volume of NaOH solution = ₂ = 27.33ml At Equivalence point No of equivalents of HNO - Hoo of equivalents of Noon MIV, = M₂ V₂ M, X 24-79 mL = 0.1063M X 27.33mL M = 0.117 Molay Answer (2) H₂SO4 +2NaOH - Given volume of Given volume of Molarity of NaOH Nasoa + 2H₂O NaOH solution required = v. = 43.89 mL H₂SO4 solution - V2 = 23-sumL. solution = M = 0.1063M n-factor of H₂SO4 =2 Too 2 Replacaeble Htione 1 M₂ = Molarity of Hy sy solution 2xM, V = MVI 2XM X 22-54mL = 0.1063M X 43.88mL = 0.1034 Molas Answer