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You dissolve 25.19 mg of arsenious acid (H3ArO3 , F.W. = 125.94) in 1.00 L of water. Arsenious acid is weak, with Ka = 5...

You dissolve 25.19 mg of arsenious acid (H3ArO3 , F.W. = 125.94) in 1.00 L of water. Arsenious acid is weak, with Ka = 5.1 × 10−10. Calculate the equilibrium concentrations of H3AsO3 and H2AsO – 3 and the pH of the solution. Assume that the activity coefficients are all 1, but you must include the autoprotolysis of water.

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Molarity - moly of solute o e tere do soluta moles at HaArg:. 25.19 mg x 1500mg x O. DOD 20 MOL yang ? - 0.00027 molarity 0:0

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