You use the equation F=1/2(kx^2). When you plug your numbers in you should get
F=(1/2)(8.25N/m)(0.150m)^2= 0.0928
3. A spring has a spring constant k=8.75 N/m. If the spring is displaced 0.150 m from its equilibrium position, what i...
Suppose a force of 40 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obeys Hooke's law, find the spring constant k. b. How much work is required to compress the spring 0.2 m from its equilibrium position? c. How much work is required to stretch the spring 0.5 m from its equilibrium position? d. How much additional work is required to stretch the spring 0.1 m if it has...
A spring of force constant 3 N/m is compressed by 5.0 em from its equilibrium position. The spring is then released and stretched by 5.0 ㎝ from its equilibrium position. Find the difference in potential energy between the two positions of the spring (stretched and compressed).
A mass-spring system with spring constant 20 N/m and mass 2.0 kg is displaced from its natural length by 20 cm. The mass is then released from this position. 1. What's the total energy as mass crosses through equilibrium position? 2. Find maximum speed.
A spring is suspended vertically from a fixed support. The
spring has spring constant k=24 N m −1 k=24 N m−1 . An object of
mass m= 1 4 kg m=14 kg is attached to the bottom of the spring. The
subject is subject to damping with damping constant β N m −1 s β N
m−1 s . Let y(t) y(t) be the displacement in metres at the end of
the spring below its equilibrium position, at time t...
A light spring with a spring constant k = 316 N/m is attached to a vertical wall at one end and a block with a mass m = 0.462 kg at the other end. The block rests on a horizontal frictionless surface and is initially at the equilibrium length of the spring. The block is then displaced from the equilibrium position of the spring in such a manner as to stretch the spring by an amount A = 0.190 m...
A spring is suspended vertically from a fixed support. The
spring has spring constant k=24 N m −1 k=24 N m−1 . An object of
mass m= 1 4 kg m=14 kg is attached to the bottom of the spring. The
subject is subject to damping with damping constant β N m −1 s β N
m−1 s . Let y(t) y(t) be the displacement in metres at the end of
the spring below its equilibrium position, at time t...
SPRING +0000000 x=0 +AX 6.5 When a spring is stretched or compressed from its equilibrium position by an amount Ar it exerts a force given by F =-kar. The - sign indicates that this force is in the opposite direction of Ar and is oriented to restore the spring to its e k is a proportionality constant called the spring constant or the force constant and is related to the stiffness of the spring. A. Draw a force vs displacement...
5 points) A spring is suspended vertically from a fixed support.
The spring has spring constant k=28 N m−1k=28 N m−1. An object of
mass m=14 kgm=14 kg is attached to the bottom of the spring. The
subject is subject to damping with damping constant β N m−1 sβ N
m−1 s. Let y(t)y(t) be the displacement in metres at the end of the
spring below its equilibrium position, at time tt seconds.
(5 poins) A spring is suspended vertically...
To stretch a certain spring by 3.00 cm from its equilibrium position requires 7.50 J of work. Part A What is the force constant of this spring? k k = nothing N/m SubmitRequest Answer Part B What was the maximum force required to stretch it by that distance? F F = nothing N SubmitRequest Answer Return to AssignmentProvide Feedback
A 0.334-kg mass is attached to a spring with a force constant of 54.9 N/m Part A If the mass is displaced 0.200 m from equilibrium and released, what is its speed when it is 0.131 m from equilibrium? ΑΣφ m/s Previous Answers Request Answer Submit X Incorrect; Try Again; 5 attempts remaining Return to Assign ment Provide Feedback