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Which orbital diagram represents the electron configuration of high-spin octahedral complex [Cr(NH3)6]2+?

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d₂2 dx?_v2 sp p гр

d₂2 dx² - y2 ep p 2ър

прес d₂2 dx² - y2 ep p 2ър

də də - у dxy dyz dyz

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Answer #1

+2 as NH3 is Neutral. & charge on cr = 42 Cras Confignation (773 do ust art configntion as [Ar] 3d Correct d2 Answers l druy

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Answer #2

I wasn't sure so I google searched it, because if you get one knewton question wrong, two more take its place. But I know for a fact that a high-spin orbital will be filled bottom row first, than top row, as well as have 1 electron before 2 in an orbital. So it would be 1 "line" in each bottom orbital, than 1 "line" in the top left orbital, with nothing in the top right orbital. 4 "lines" in total, 1 in each bottom orbital, than the last one in top left.

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