Question

NAME _DATE SECTION INSTRUCTOR und to be EXERCISE 10 Moles Show calculation setups and answers for all problems. 1. Find the molar mass of (a) nitric acid, HNO; (b) potassium bicarbonate, KHCO3, and (e) Nickel(II) nitrate, Ni(NO). (b) 2. A sample of mercury(II) bromide, HgBro, weighs 8.65 g. How many moles are in this sample? 3. What is the mass of 0.45 mol of ammonium sulfate, (NH),SO.? 4. How many molecules are contained in 6.53 mol of nitrogen gas, N,? 5. Calculate the percent componition by mass of calcium sulfite, Caso,

Answer 1

K= 39 O = 16 N = 14 Ni = 959 Hg = 201 By = 80 S 321 HNO3 = 1 +14+ 3X16 = 15+48 = 63 g/mol kroz = 39+1+12+ 3x16 = 110 almol Ni(NO3), 59+2x14+ 6x16 = 183 glimp 8.659 -0.024 mot mole of Ng Bry - motor mass 361 g not 420 (2) mass more My Bry = 201 + 80X2 = 201 +160 = 361 g/mol muss 3 mole = molar mass ma Mass = mole x molarmas (NH4) S04 = 2XN + 8 xH + IXS + 4XO 2x14 +ex! + 1X32 + 4x16 = 20 + 8 +32 toy = 132 g/mol molar mass mass = 0.45X132 = 59.4 gram 2 A) Imol N2 = 6:023 x 1023 molecule Na 6.53 mol N₂ = 6.53 26 023X1023 = 39.33 X1023 = 3.933 X10 Nz Molecules PAGE TO Ans 3.933 X 1024 chuttle

Relective mol = divided by least mot DATE OUT Number mass of a (5) 7. of Ca = Total mass of (aso 4 in 1 mol sout 40 136 51 -4.325 40+32 + U X16 = UO +32 +64 for Ca - 136 gram to xloo = 29.41 %. Symbol Amount mol. Number (6) 51.90% = C = 51.90 gram = 9.20%. = Ha = 9.00 gram = 9.80 = 9.80 30.30% = C1 = 38.30 gram = Relative mote Number mole of c = 4.325 4.325 - 4.04 = 4 mole of t = 9.00 9.00/1.07 = 9.15 7 9 mole of cl = 1.07 1.07 = 1 38.30 =1.07 35.5 C:H 4 a 9 4 >. (C4 Hg Cl, Empirical formula classmate PAGETT

O2 mass more molarmes DATE 32 23 Oz mos) = 16X2=3 / bagoners mol of 02 = 28.4 - = 0.00 45 motor I mol O2 = 6.02281033 3 0.8875 mol O2 = 6.0228102 x 0.88155.34x los molecules mol of 0 = 28.4. = baas met ofe Imel Oxygen atom = 6:022 X 1023 11.775 mol = 1.77586 022X1023 €1.0 8) 48.6 means. 48 gram 'm loogrom Mixture * 100 gram Contain = 40 g Nasi I gram = 48 74 gyerm mixture 40 x94 100 74 gram Contin e Too = 35.52 gram. mass of (9) 6.022 X 1023 mol ) = 13 gram Nuz 2.6X1023 molecule mass = 3, yay x2-xt'? 7.34 gram) classmate NM2

molar mass of 25oy = 2 + 2x 16x4 = id glanol DATEID 10) density = 1.67 g/me. l of H₂500 = 75.1. molavity = fx dx lo moler mass 75 X 1.678 10 12525 go go molarity = 12.70 mol/L 12 contain = 12.78 mol I in 400 ml (0.4L) Contain= 12.788 0.4 = 5.112 mol H₂SO y in gou me a Thank you very much Good luck