How much work is required to stop an electron (m = 9.11 \times 10^ - 31 kg) which is moving with a speed of 2.10

Question

Question

science physics

Answer 1

Answer #1

yeah... the question is a little ambiguous. But if the electron is slowed down, you have to do negative work on it.

initial KE = (1/2) m v^2 = (1/2) * 9.11 x 10^-31 * (2100000)^2 = 2.009 x 10^-18 Joules

final KE = 0

work done on electron = final KE - initial KE =

= 0 - 2.009 x 10^-18 J

= - 2.009 x 10^-18 J

Answer 2

Similar Homework Help Questions

How much work is required to stop an electron (m 9.11 x 10-31 kg) which is...

How much work is required to stop an electron (m 9.11 x 10-31 kg) which is moving with a speed of 1.50x108 m/s? Express your answer to three significant figures and include the appropriate units. ? W = Value Units Submit Request Answer How much work is required to stop an electron (m 9.11 x 10-31 kg) which is moving with a speed of 1.50x108 m/s? Express your answer to three significant figures and include the appropriate units. ? W...
How much work is required to stop an electron (m=9.11×10−31kg) which is moving with a speed...

How much work is required to stop an electron (m=9.11×10−31kg) which is moving with a speed of 1.90×106 m/s ? Express your answer to three significant figures and include the appropriate units.
How much work is required to stop an electron (m=9.11×10−31kg) which is moving with a speed...

How much work is required to stop an electron (m=9.11×10−31kg) which is moving with a speed of 1.40×106 m/s ? Express your answer to three significant figures and include the appropriate units.

Part A How much work is required to stop an electron (m=9.11 x 10 31 kg)...

Part A How much work is required to stop an electron (m=9.11 x 10 31 kg) which is moving with a speed of 1.70*10m/s ? Express your answer to three significant figures and include the appropriate units. НА W= 1.64.10 18 J Submit Previous Answers Request Answer * Incorrect: Try Again; 3 attempts remaining Provide Feedback Type here to search
How much work is required to stop an electron (m=9.11x10^31kg) which is moving with a speed...

How much work is required to stop an electron (m=9.11x10^31kg) which is moving with a speed of 1.30x10^6m/s ?
Use the work-energy theorem to find the force required to accelerate an electron (m=9.11 * 10^-31...

Use the work-energy theorem to find the force required to accelerate an electron (m=9.11 * 10^-31 kg) moving along the x axis from 4.00 * 10^6 m/s to 1.60 * 10^7 m/s in a distance of 0.0125 m. Answer: 8.75 * 10^-15 N Please Explain :)

An electron of mass 9.11 10-31 kg has an initial speed of 2.85 105 m/s. It...

An electron of mass 9.11 10-31 kg has an initial speed of 2.85 105 m/s. It travels in a straight line, and its speed increases to 6.93 105 m/s in a distance of 5.50 cm. Assume its acceleration is constant. (a) Determine the force exerted on the electron. (b) Compare this force with the weight of the electron, which we neglected. F weight of the electron =
An electron (m = 9.11×10−31 kg ) is accelerated from rest to speed v by a...

An electron (m = 9.11×10−31 kg ) is accelerated from rest to speed v by a conservative force. In this process, its potential energy decreases by 7.30×10−14 J . Part A Determine the electron's speed, v. v v = nothing ⋅c
Part A m, how fast is the The mass of an electron is 9.11 x 10-5 kg. If the de Broglie wavelength for an electron...

Part A m, how fast is the The mass of an electron is 9.11 x 10-5 kg. If the de Broglie wavelength for an electron in a hydrogen atom is 3.31 x 10- electron moving relative to the speed of light? The speed of light is 3.00 x 10 m/s Express your answer numerically as a percent. View Available Hint(s)

A beam of electrons (m - 9.11 * 10-31 kg/electron) has an average speed of 2.1 x 10 m/s. What is the wavelength...

A beam of electrons (m - 9.11 * 10-31 kg/electron) has an average speed of 2.1 x 10 m/s. What is the wavelength of electrons having this average speed, in picometers? pm Submit Show Approach Show Tutor Steps