The answer is given as follows

CHA CH₂ + H₂C Mai H₂C • treating 1,3-butadiene w/ one mole of HCl give a mixture ok 2 isometric products. Draw curv...
CI ACH H C HCI CH, . CH HCVCH Ch, aw CH Treating 1.3 pentadiene with one mole of HCl give a mixture of electrons in this step of the reaction mechanism Arrow pushing Instructions H2C c hs :: —
CH3 CH3 CH3CH2C=CH2 + CH2OH 12304, CH3CH,Ć-OCHz CH3 Treating 2-methyl-1-butene with methanol in the presence of sulfuric acid gives 2-methoxy-2-methylbutane. Draw curved arrows to show the movement of electrons in this step of the reaction mechanism. Arrow-pushing Instructions no XT CH3. HO CH₂ H-ö-CH3
37. H0+ (CH3), C CH OH alkene + H2O Draw the structure of the major alkene product of this acid-catalyzed dehydration. (Hint: rearrangement.) 38. alkenes Three alkenes produce butane when treated with hydrogen and platinum. Draw their structures. + H-Br - 39. CH2=CH CH3 CH2-CH-CH, H Br The first step of the mechanism of this reaction produces two carbocations. Draw both and circle the one that is more stable. ODHO Br 11 =C + Br - Br - - Br...
Chapter 6 [References) Question 15 1 pt CI CI Question 16 1 pt HCI H3C CH3 HC Question 17 CH3 H3C CH3 1 pt Question 18 1 pt H2C CH3 CI Question 19 1 pt CH3 H2C CH3 CI Question 20 1 pt Question 21 ® 1 pt Treating 1,3-pentadiene with one mole of HCl give a mixture of five isomeric products. Draw curved arrows to show the movement of electrons in this step of the reaction mechanism Question 22...
NaOH, Br CH,NH + CO2 H20 H₃C' `NH₂ Amides can be converted into primary amines with the loss of a single carbon atom by the Hofmann rearrangement base Draw curved arrows to show the movement of electrons in this step of the mechanism Arrow.pushing Instructions Br H3C N Submit Answer Try Another Version 1 Hemattempt remaining
pathway, substitution or elimination, will predominate and so a mixture of products is frequently observed. In contrast to the El reaction which involves a carbocation intermediate, the ElcB reaction takes place through a carbanion intermediate. Base-induced abstraction of a proton in a slow, rate-limiting step gives an anion which then expels the leaving group from the adjacent carbon. The reaction is particularly suited to the elimination of substrates which contain poor leaving groups two carbons removed from a carbonyl group....
2 problems
REVIEW Topics [References) CH HC OCH Br2 CH3 B H3C CH,OH H₂C CH₂ Electrophilic addition of hypohalous acids to alkenes yields a 1,2-haloalcohol called a halohydrin. Halohydrin formation, however, does not result from the addition of HOBr, for example. Instead the addition is done indirectly by reaction of the alkene with Br, in the presence of water. The reaction also works with Cl2 to give chlorohydrins instead of bromohydrins. The reaction proceeds through a cyclic intermediate known as...
сн, Нас 12-addition products (direct addition) CH2 CH3 Н,с Н-с CH CI HCI CH2 Cн Н.с 1,4-addition products (conjugate addition) Cн CH3 Нас Н.С CI Electrophilic addition to an alkene proceeds via Markovnikov regiochemistry due to the formation of the more stable carbocation intermediate. In the case of conjugated dienes, that is dienes that are separated by one sigma bond, the carbocation that is formed is stabilized additionally by resonance. Addition of the nucleophile to the carbocation intermediate can therefore...
CH3 CH3 1. Hg(OAC), H20 2. NaBH НО, І CH3 CH, Hoc H₃C/ Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H adds to the sp carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov...
CHO 1. NH2OH 2. Ac2o 3. CH,O CHO OH H- HO H HO H HCN H OH OH H- OH H- -OH H- CH2OH CH2OH The Wohl degradation is a series of reactions that shorten an aldose chain by one carbon, it is almost the exact opposite of the Kiliani In this reaction the aldose aldehyde carbonyl group is converted into a nitrile. The resulting cyanohydrin loses HCN under basic cone Conversion of the aldehyde to a nitrile is accomplished...