Calculate the number of grams of solute in 536.5 mL of 0.278 M calcium acetate.
Answer:
Step 1: Explanation:
Molarity is defined to be the number of moles of solute divided by the volume of solution (in L )
i.e Molarity = number of moles of solute / volume of solution ( in L )
Step 2: Calculate the moles of calcium acetate
Given, volume = 536.5 mL = 0.5365 L [ because 1 L = 1000 mL So , 536.5 mL × ( 1 L / 1000 mL ) = 0.5365 L ]
Molarity =0.278 M
Hence by using above equation
Molarity = number of moles of solute / volume of solution ( in L )
=> moles = molarity × volume = ( 0.278 M × 0.5365 L )= 0.149147 mol
Step 3: Calculation of mass( in grams)
Mass = molar mass × moles = ( 158.166 g/mol × 0.149147 moles ) = 23.59 g
Calculate the number of grams of solute in 536.5 mL of 0.278 M calcium acetate.
Calculate the number of grams of solute in 915.5 mL of 0.295 M calcium acetate.
Calculate the mass, in grams, of calcium acetate that must be added to a 500-mL volumetric flask in order to prepare 500 mL of a 0.238 M aqueous solution of the salt.
How many grams of solute are present in 245 mL of 0.600 M KBr? mass of solute: Calculate the number of moles of solute in 27.89 mL of 0.1125 M K,Cr,0, (aq). moles of solute: mol
Explain how 350. mL of 0.650 molar calcium acetate can be prepared from solid magensium acetate? How would you prepare 1.75 liters of 0.750 molar sodium hydroxide if the course of sodium hydroxide was 3.5 liter bottle of 2.55 M sodium hydroxide? Calculate the maximum mass of sodium phosphate that can be recovered from 225 mL of 0.85 M aqueous sodium phosphate? Calculate the maximum volume of 1.25 M NaOH that can be neutralized by 4.00 liters of: 0.75 M...
3 attempts left Check my work Enter your answer in the provided box. Calculate the number of grams of solute in 137.1 mL of 0.258 M calcium acetate. g solute
Calculate the number of grams of solute that has to be used to make the following solution: 245.3 mL of 0.283 M C6H12O6 (glucose)
Calculate the number of grams of solute in 0.250 L of 0.200 m KBr
Part A Calculate the grams of solute in 25.0 mL of a 2.50%m/v solution of fructose. IVO AND A 0 0 ? Submit Request Answer
5. How many milliliters (mL) of a 3.277 M calcium nitrate solution would contain 76.50 grams of calcium nitrate solute?
Calculate the number of moles of solute in 80.69 mL of 0.1425 M K2Cr2O7( aq ). moles of solute: mol