Question

Calculate the number of grams of solute in 536.5 mL of 0.278 M calcium acetate.

Calculate the number of grams of solute in 536.5 mL of 0.278 M calcium acetate.

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Answer #1

Answer:

Step 1: Explanation:

Molarity is defined to be the number of moles of solute divided by the volume  of solution (in L )

i.e Molarity = number of moles of solute / volume of solution ( in L )

Step 2: Calculate the moles of calcium acetate

Given, volume = 536.5 mL = 0.5365 L [ because 1 L = 1000 mL So , 536.5 mL  × ( 1 L / 1000 mL ) = 0.5365 L ]

Molarity =0.278 M

Hence by using above equation

Molarity = number of moles of solute / volume of solution ( in L )

=> moles = molarity × volume = ( 0.278 M × 0.5365 L )= 0.149147 mol

Step 3: Calculation of mass( in grams)

Mass = molar mass × moles = ( 158.166 g/mol × 0.149147 moles ) = 23.59 g

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