Calculate the number of grams of solute in 915.5 mL of 0.295 M calcium acetate.

Question

Question

Calculate the number of grams of solute in 915.5 mL of 0.295 M calcium acetate.

science chemistry

Answer 1

Answer #1

Molar mass of calcium acetate = 158.17 g/mol

0.295 M solution means, there is 0.295 mol of calcium acetate in 1000 mL of solvent.

Mass of 0.295 mol of calcium acetate = 0.295 x 158.17 g = 46.66 g

1000 mL of solution contains solute = 46.66 g

915.5 mL of solution contains solute = (46.66 x 915.5)/1000 g = 42.72 g

Answer 2

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