Based on the weight percent of the P2O5 in your fertilizer sample, calculate the % of phosphorus(P) in your fertilizer sample.
Information needed to do problem: weight percent of P2O5 in fertilizer: 31.168%
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Hi,
to determine the actual amounts of phosphorus in your fertilizer, we will use the following formula:
% P 2 O 5 � 0.44 = % P
Therefore,
A fertilizer containing 31.168% P 2 O 5 has about 14% P (31.168% P 2 O 5 � 0.44 = 13.71% P)
Based on the weight percent of the P2O5 in your fertilizer sample, calculate the % of phosphorus(P) in your fertilizer...
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Suppose you analyze a sample of fertilizer by the procedure of this experiment and obtain 1.000g of MgNH4PO4 * 6H20. Calculate the equivalent mass of P2O5 initially in the sample. I do not understand what the equivalent mass is.
Classi Part A
Consider the reaction
2H3PO4→P2O5+3H2O
2
H
3
P
O
4
→
P
2
O
5
+
3
H
2
O
Using the information in the following table, calculate the
average rate of formation of P2O5
P
2
O
5
between 10.0 and 40.0 s
s
.
Time (s
s
) 0 10.0 20.0 30.0 40.0 50.0
[P2O5]
[
P
2
O
5
]
(M
M
) 0 2.50×10−3 5.50×10−3 7.30×10−3 8.50×10−3 9.10×10−3
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