Question

Strontium chromate, SrCrO4, has a Ksp value of 4.00×10−5 . What happens when strontium and chromate solutions are mixed to give 2.00×10−2 M Sr2+ and 1.50×10−3 M CrO42−?

Answer 1

SrCrO₄(s) <-----> Sr²⁺(aq) + CrO₄^2-(aq)

K_sp = [Sr²⁺]*[CrO₄^2-]

Now, when [Sr²⁺] = 2*10^-2 M & [CrO₄^2-] = 1.5*10^-3 M

Then reaction quotient, K_q = [Sr²⁺]*[CrO₄^2-] = 3*10^-5

Since, K_q < K_sp , therefore dissolution will occur