Even at high temperatures, the formation of NO is not
favored:
(Kc = 4.10 ×10−4 at 2000°C)
N2(g) + O2(g) ⇌ 2
NO(g)
What is [NO] when a mixture of 0.20 mol of
N2(g) and 0.17 mol of O2(g)
reach equilibrium in a 1.0−L container at 2,000°C?
![0.20 mor = 0.20 M [2) = Tool [02] = Oolt moe - Oolfa 1.0 N2 (9) + O2 (9) 7 21019) ſ 0.20 0.17 c -a -n 2a E 10.20-a) (0.14-a)](http://img.homeworklib.com/questions/3e84d3a0-0dc5-11ea-9873-9b6f82073596.png?x-oss-process=image/resize,w_560)
Even at high temperatures, the formation of NO is not favored: (Kc = 4.10 ×10−4 at 2000°C) N2(g) + O2(g) ⇌ 2 NO(g) What...
#17.10
Enter your answer in the provided box. Even at high temperatures, the formation of NO is not favored: (K = 4.10 x 10-4 at 2000°C) N2(g) + O2(g) = 2 NO(g) What is [NO] when a mixture of 0.20 mol of N2(g) and 0.17 mol of O2(g) reach equilibrium in a 1.0-L container at 2,000°C? M
apter 17 Homework Saved 1 attempts left Check my work Enter your answer in the provided box. Even at high temperatures, the formation of NO is not favored: (K. = 4.10 X 10 - at 2000°C) Hook N2(g) + O2(2) = 2 NO() nint rences What is [NO] when a mixture of 0.20 mol of N2(g) and 0.20 mol of O2(e) reach equilibrium in a 1.0-1 container at 2,000°C? Repc M Guld
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explanation
1. even at a high temperature, the formation of NO is
not favored.
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