Question

Attempt 2 of Unlimted 7.4 Section Exercise Question 18 of 18 (1 point) College tuition: A simple random sample of 40 colleges and universities in the United States has a mean tuition of $17,900 with a standard deviation of $10,500. Construct a 99% confidence interval for the mean tuition for all colleges and universities in the United States. Round the answers to the nearest whole number A 99% confidence interval for the mean tuition for all colleges and universities is

Answer 1

Solution:

Get the 99% confidence interval in TI 83 as

2ND>VARS>TESTS>T INTERVAL

TEXAS INSTRUMENTS TI-83 Plus TInterval Inpt: Data Stats X: 17900 Sx: 10500 n: 40 C-Level:.99 Calculate TEXAS INSTRUMENTS TI-83 Plus TInterval (13404,22396) X=17900 Sx=10500 n=40 Ans+1 STATPLOT F TRISET 2 FORMAT CALCR WINDOW ZOOM TRACE TABLE F5 GRAPH Y= TNTPLOTF: TESET F WINDOW ORMATS CALCRTABLES ZOOM TRACE GRAPH QUIT INS DEL 2nd MODE A.LOCK LINK LIST ALPHA X.T.@.n STAT TESTA ANGLE DRAWC DISTR

You get

99% confidence interval for mean as

13404<mu<22396

ANSWER:

13404<mu<22396