Question

Determine the identity of the daughter nuclide from the beta decay of xC. (a) , x N.(b), xB.(c) , X N (d), XBe ,(e) XC.

Answer 1

Following is the - complete Answer -&- Explanation: for the given Question: in.....typed format...

$\Rightarrow$Answer:

Option - ( a ) and Option - ( b )

$\Rightarrow$Explanation:

Following is the complete: Explanation: for the above: Answer:

• Step - 1:

We know: the following cases, and results of positive and negative beta ( $\beta$ - decay ): of an element: ^A X _Z  ; where:

1. X = symbol of the element
2. A =  atomic weight of element ' X ' .
3. Z =  atomic number of element ' X '

​​​​​​​$\Rightarrow$ In case of positive beta decay: we will get:

  ^A X _Z $\rightarrow$   ^A Y _Z-1 + e ⁺OR  $\beta$⁺   + v_e

$\Rightarrow$In case of negative beta decay: we will get :

   ^A X _Z $\rightarrow$   ^A Y _Z+1 + e ^-OR  $\beta$^-   + v_e

• Step - 2:

​​​​​​​$\Rightarrow$ Let's assume: we are dealing with positive and negative: beta decay (  $\beta$⁺and $\beta$ ^- ) of  carbon atom ( C ) :

Therefore we will be getting the following products OR daughter nuclides : of the beta decay of ¹⁴C₆

• Step - 3:

​​​​​​​​​​​​​​$\Rightarrow$ In case of positive beta decay: we will get:

  ¹⁴C₆$\rightarrow$¹⁴B₅ + e ⁺OR  $\beta$⁺   + v_e-----------------i.e. Option - ( b ) ; Answer

And:

$\Rightarrow$In case of negative beta decay: we will get :

   ¹⁴C₆$\rightarrow$¹⁴N₇  + e ^-OR  $\beta$^-   + v_e --------------- i.e. Option - ( a ) ; Answer

$\Rightarrow$ Therefore: the above: satisfies the Answers: we have stated above.

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