Question

1) Calculate 4G rx (350 K) for the reaction: H2O(g) +0.502(g) → H2O2(1) using the Gibbs-Helmholtz equation and (46°F 2120-228.57 kJ/mol; 4G°F (H202)-120.35 kJ/mol; Hºr ano)-241.82 kJ/mol; AHF (H202)=-198.78 kJ/mol). You may assume that the difference between 4GºrxN and AHørxn is temperature independent.

Answer 1

RESULT:

1. 
   AGRXN (350K) = 119.56 kJ/mol
   

SOLUTION:

- Given reaction: H2O(g) +0.502 + H2O2(e) We know that, std. Gibbs free energy: AGPAN = {AG* (products) - EAG• Creactanto) = 4G09 (4202) – (Ago (web) + 4G+ (02)) = -120.35 Kimo - (-228.57 kJ/mol to) :Ag?m= 108-22 KJ /mol similarly, alloren is given by, Ahorn Ohe (products) - s ahir (reactants) AH (1402) - (SHi Chel) + DHy(0.) = +98.78 kJ/mol - (-241-82 Külmol + o) oriyxn = - 4304 kJ/mol from Gibbs - Helm holtz equation, 12 -66 () tou, ( 7 ) rive have, T2 = 350k, Ti = 298 K (room temp) .: alarmen = 105-22 Kilman kan fork) + 43 04 silinen elinked to ease .: D Gran = 127.04 kſ (mo! - 7.48 KJ/mol

|: AGren at 350k = 119.56 kJ/mo)?