Question

(y + 1000-y)dy-kdt Compute P and Q: 0.001 1000 Q 0.001 1000 Hint Video (.mp4) Hint Video (.wmv) Part 3 of 5 Now integrate both sides to get an equation relating y and t, but one that also includes two constants: the proportionality constant k and a constant C that comes from integrating (as in part 2 of the previous problem, you can combine the integration constants into one +C" on the right side). Because 0 s y s 1000, you can replace lyl by just y, and 11000 - yl by just 1000-y Solve the resulting equation for y. It turns out that the answer looks cleanest if you let A - e1000C, and just use A instead. This is fine since it's just an unknown constant in any case, and we will use initial conditions in the next step to solve for both k and C and/or A. Your answer above should involve the variable t and the constants k and A, where A e1000c, Hint Video (.mp4) Hint Video (.wmv)

Answer 1

Infegroting both sides lo0o-J oo0 aking ex ponential e. foo0 C looo oookt e. looo kt +A e A(1000e = oo0c