Question

Please help me with this and explain thank you

Review Problem 5.030 Assign oxidation numbers to the atoms in the following: (а) CIO4 Element Oxidation Number CI *1 о *2. Answer 1: exact number, no tolerance Answer 2: exact number, no tolerance (b) CІ" Oxidation Number: exact number, no tolerance (c) SF6 Oxidation Number Element 1 F Answer 1: exact number, no tolerance Answer*2: exact number, no tolerance (d) Au(NO3)3 Element Oxidation Number Au 1 N 2 о 3 Answer 1: exact number, no tolerance Answer*2: exact number, no tolerance Answer *3 exact number, no tolerance

Answer 1

a)

Oxidation number of O = -2

lets the oxidation number of Cl be x

use:

4* oxidation number (O) + 1* oxidation number (Cl) = net charge

4*(-2)+1* x = -1

-8 + 1 * x = -1

x = 7

So oxidation number of Cl = +7

Oxidation number of each element in ClO4-1 is

Cl=+7

O=-2

b)

lets the oxidation number of Cl be x

use:

1* oxidation number (Cl) = net charge

1* x = -1

0 + 1 * x = -1

x = -1

So oxidation number of Cl = -1

Oxidation number of each element in Cl-1 is

Cl=-1

C)

Oxidation number of F = -1

lets the oxidation number of S be x

use:

6* oxidation number (F) + 1* oxidation number (S) = net charge

6*(-1)+1* x = 0

-6 + 1 * x = 0

x = 6

So oxidation number of S = +6

Oxidation number of each element in SF6 is

S=+6

F=-1

d)

This is compound of Au+3 and NO3-

So, oxidation number of Au is +3

Oxidation number of O = -2

lets the oxidation number of N be x

use:

3* oxidation number (O) + 1* oxidation number (N) = net charge

3*(-2)+1* x = -1

-6 + 1 * x = -1

x = 5

So oxidation number of N = +5

Oxidation number of each element in NO3-1 is

Au=+3

N=+5

O=-2