Question

An oxidic mineral contains w% 72% Al2O3. What is the theoretical yield of pure aluminium that can be obtained from a 2.00 kg mineral sample? Calculate the amount of material and the dimensions (g).

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Answer 1

Al2O3 ---------> 2 A1 Mass of mineral = 2.00 kg = 2000 g We know that -*100 mass of solute mass percent = mass of solution mass of A1,02 mass percent = -x100 mass of mineral 79mass of A1,02 03 x100 2000 g mass of A1,03 = -4 72 x 2000g 10 "8=1440 g 100 Number of moles of Al2O3 = mass/mol.wt. = 1440 g/(101.96 g/mol) = 14.12319 mol 1 mole of Al,03 produces 2 moles of Al Number of moles of Al = 2* 14.12319 mol = 28.24637 mol Mass of Al = moles * mol.wt. = 28.24637 mol * 26.98 g/mol = 762.087093 g Mass of Al = 762 g