Question

Given the spectra determine the molecular formula and structure m/z = 171

Unknown 1H 13C-NMR 160 210 190 180 110 80 50 20 200 170 150 140 130 100 40 10 240 230 220 120 f1 (opm) 60 30 -125.65 Unknown 1H 'H-NMR expansion 7.55 7.50 745 7.30 7.90 7.85 7,75 7,70 765 7.60 7.35 7.25 7,15 7BC 740 7.20 7,10 f1 (opm) PerkinElmer Spectrum Version 10.03.09 Friday, 8 March 2019 2:51 PM Analyst Analyst3 Friday, 8 March 2019 2:51 PM Date 99 98 97 494 38cm-1, 97.00% h 16 53cm-1, 96 509%T 96 1182.79c-1,95.81%T 95 1572.82cm-1, 94.9496T 905.83cm-1. 94.6096T 94- 555 90cm-1, 93 93 806.50cm-1, 279%T 667.26cm-1,92.21%T 92- 1302 35cm-1,92.b9%T 88 %T 3122.02cm-1, 91 102.01cm-1,91.37%T 526.41am-1, 9 90 89 1147.84cm-1, 89.14 % T 88 1321.40cm-1, 87.80 %T 87 3320.26cm-1, 87 08%T 86 3234.54cm-1, 85.42 %T 4000 500450 3500 3000 1500 2000 1000 2500 cm-1 1%

Answer 1

13 C NMR =

1. two aromatic carbon present at 125 and 129 ppm, hence benzene ring confirm.