Question

QUESTIONS: 1. What is/are the purpose(s) of adding HCl to the reaction mixture? 2. In this experiment, the moles of reactants and products, rather than their concentrations, are used to compute the equilibrium constant. Why does this work? Show calculations to support your answer. 3. Write an equilibrium constant expression for a hypothetical reaction, A + B = X + 2Y. Can you use the moles of reactants and products at equilibrium, rather than their concentrations, to calculate the equilibrium constant? Explain.

The reaction is CH3COOH + C2H5OOH—->CH3COOC2H5 + H2O

Answer 1

(1) CH₂-d-OH + CASCHI CHI ester? 1 Carid (alcohol) + H2O He has been added to act as catalyst . HCl (ht) is attacking at (e=o) oxygen atom of ester thereky protonating it and facilitating the reaction et towards product side. It helly is generating electrophitic centre at carbonyl carbon. 2) According to eg. © when moles used K- Nester nego noud nalichol n: no. of moles

When Concentration used; K= [Ester] [H₂o ] Acid] Talcohol] ao concentration = moles Volume.

K= nester the Malcohol К? Пеет до - navid Malcohol Thus, it does not matte & does not matter whether we ase concentration terms or moles term is this case because - i Reactants are reacting in 1:1 mole ratio " Equal moles of reactants and equal moles of products are there (le, 2) that's why rolume term is getting cancelled AIB ² x + 2Y K= [x] [Y] 2 - ④ 143 183 K= px (nyl - Mx Ny ² MAMBX) "Voleme term is not getting cancelled u we cannot use simple number of moles term for calculating equilibrium constant We need value of concentration term.