Question

A system has a common checkout line for customers to wait to be served by one of four servers. Every customer arrives ba...

A system has a common checkout line for customers to wait to be served by one of four servers. Every customer arrives based on an exponential distribution with mean .5 minutes and it takes Tria(1, 2, 3) minutes for checkout processing. Ignoring the time to walk from the queue to the server, what is the steady state utilization? Is the system stable?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

If a system behavior is independent of initial conditions and the elapsed time, then the behavior of Queue is said to be steady state behaviour.

The state of queuing system is represented by a single number n, the number of customers currently in the system.

 It utilizes memory-less property of exponential distribution. As per this property the time since the last arrival and the time the current customer has been in the service process are irrelevant to the future behavior of the system.

 Consider the system to be in steady state, which means that the system has been running for so long that the current state doesn’t depend on the starting condition.

 By computing the long run probabilities of being in each state, we will determine the performance measures of queuing models as long term steady state performance measures

 Hence, the customers arrive only one customer at a time. The system state can change only by one unit at a time.

Add a comment
Know the answer?
Add Answer to:
A system has a common checkout line for customers to wait to be served by one of four servers. Every customer arrives ba...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A system has a common checkout line for customers to wait to be served by one...

    A system has a common checkout line for customers to wait to be served by one of four servers. Every customer arrives based on an exponential distribution with mean .5 minutes and it takes Tria(1, 2, 3) minutes for checkout processing. Ignoring the time to walk from the queue to the server, what is the steady state utilization? Is the system stable?

  • For the following problems compute (a) utilization, (b) average time a customer waits in the queue,...

    For the following problems compute (a) utilization, (b) average time a customer waits in the queue, (c) average number of customers waiting in the queue, (d) average number of customers in service, (e) the average time a customer spends in the system. Problem 1. An average of 10 cars per hour (with variance 4) arrives at a single-server drive-in teller. Assume that the average service time for each customer is 5.5 minutes (with variance 5). Problem 2. Customers arrive to...

  • Problem 3 Consider a single-server queueing system that can hold a maximum of two customers exclu...

    Problem 3 Consider a single-server queueing system that can hold a maximum of two customers excluding those being served. The server serves customers only in batches of two, and the service time (for a batch) has an exponential distribution with a mean of 1 unit of time. Thus if the server is idle and there is only one customer in the system, then the server must wait for another arrival before beginning service. The customers arrive according to a Poisson...

  • QUESTIONS For MM: GD queuing system with 2 servers of service rate =40 customers per hour...

    QUESTIONS For MM: GD queuing system with 2 servers of service rate =40 customers per hour per server and arrival ratei - 45 customers per hour, on the verge, how long in minutes) does a customer wait in line round off to 2 decimal digits) QUESTION 10 A small branch bank has two teller, one for deposits and one fow withdrawals Cistomers arrivent arch teller's window with an average rate of 20 customers per hour. The total customer anivartes per...

  • Question 1 Unless otherwise stated, assume all times reported refer to averages from exponential distributions and...

    Question 1 Unless otherwise stated, assume all times reported refer to averages from exponential distributions and that we are looking at stable processes. If the average time between arrivals is 10 minutes, what is the arrival rate? a. 6 jobs per hour b. 0.1 jobs per minute c. 0.001666 jobs per second d. All of the above 1 points Question 2 For a system with a single server, if the arrival rate is six jobs per hour and the average...

  • 56) One employee is in charge of the following activities at a refreshment stand: Activity Greet...

    56) One employee is in charge of the following activities at a refreshment stand: Activity Greet customer Take order Process order Print receipt Activity Time per Customer 5 seconds 25 seconds 1.5 minutes 30 seconds If demand rate is 20 customers per hour, what are the flow rate (in customers per hour), utilization, and cycle time (in minutes per customer)? A) 20, 0.83, 0.05 B) 24, 1, 0.04 c)20,0.83, 3 D) 24, 1,25 57) Patients are arriving at a clinic...

  • Consider a simple queuing system in which customers arrive randomly such that the time between successive...

    Consider a simple queuing system in which customers arrive randomly such that the time between successive arrivals is exponentially distributed with a rate parameter l = 2.8 per minute. The service time, that is the time it takes to serve each customer is also Exponentially distributed with a rate parameter m = 3 per minute. Create a Matlab simulation to model the above queuing system by randomly sampling time between arrivals and service times from the Exponential Distribution. If a...

  • 3. For a single-server, single-line, single-phase waiting line system, where l represents the mean arrival rate...

    3. For a single-server, single-line, single-phase waiting line system, where l represents the mean arrival rate of customers and m represents the mean service rate, what is the formula for the average utilization of the system? a) l / m b) l / (m-l) c) l2 / m(m-l) d) 1 / (m-l) e) l / m(m-l) 4. For a single-server, single-line, single-phase waiting line system, where l represents the mean arrival rate of customers and m represents the mean service...

  • 15 customers arrive every hour​ at Andy​ Johnson's food truck when it parks outside the Orlando...

    15 customers arrive every hour​ at Andy​ Johnson's food truck when it parks outside the Orlando Courthouse from... Table: Average Number of Customer in Waiting Line Poisson​ Arrivals, Exponential Service Times Number of Service​ Channels, M rhoρ 1 2 3 4 5 0.1 0.0111 0.15 0.0264 0.0008 0.2 0.05 0.002 0.25 0.0833 0.0039 0.3 0.1285 0.0069 0.35 0.1884 0.011 0.4 0.2666 0.0166 0.45 0.3681 0.0239 0.0019 0.5 0.5 0.0333 0.003 0.55 0.6722 0.0449 0.0043 0.6 0.9 0.0593 0.0061 0.65 1.2071...

  • QUESTION 1 Customers arrive at a hair salon according to a Poisson process with an average of 1...

    QUESTION 1 Customers arrive at a hair salon according to a Poisson process with an average of 16 customers per hour. Which of the following is most likely true, based on this information: a. The hair salon serves customers on a walk-in basis (rather than by appointment times) b. If 10 customers arrive in the first hour, it is likely that 22 customers will arrive in the next hour. c. If the salon can serve an average of 20 customers...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT