Question

PLEASE ANSWER ALL PARTS OF THE QUESTION: Case1, Case 2: a,b

••• Weekly Comprehensive Assign ® V Weekly Comprehensive Assign X + a pp varafy.com/lti/v1p1?custom assignment_revision_resource_id=5dcf22405b33ca000406f4ae&custom_attempt_penalties=0&cust... Q € > c S # D Heat Conduction Heat conduction occurs through any material, represented here by a rectangular bar, whether window glass or walrus blubber. The temperature of the material is T2 on the left and T1 on the right, where T2 is greater than T1. The rate of heat transfer by conduction is directly proportional to the surface area A, the temperature difference T2 - T1, and the substance's conductivity k. The rate of heat transfer is inversely proportional to the thickness d. Q kA (T2 - T1) where Q/t is the rate of heat transfer in watts, k is the thermal conductivity of the material, A and d are its surface area and thickness, and (T2 - T1) is the temperature difference across the slab. Material having thermal conductivity k Area A Case 1. A window in a house has a rectangular shape of 2.0 m by 1.0 m. The glass in the window is 0.5 cm thick, with a thermal conductivity of 0.84 W/(m °C). The temperature in the house is 18.0°C, and the temperature outside is 4 °C. How much heat is lost through this window in one minute? Don't use scientific notations Enter a number J Submit (5 attempts remaining) Case 2 A Styrofoam ice box has a total area of 0.950 m- and walls with an average thickness of 2.50 cm. The Styrofoam's thermal conductivity is 0.010 W/(m ºc). The box contains ice, water, and canned beverages at 0°C. The inside of the box is kept cold by melting ice. If the ice box is kept in the trunk of a car at 34.0 °C, (a) How much heat is transfered to the inside of the box in One Hour? Enter a number J Submit (5 attempts remaining) (b) How much ice melts in One Hour? The latent heat of fusion for water is 3.4x10J/kg.. Keep 3 decimal places. Enter a number kg Submit (5 attempts remaining)

Answer 1

Just follow the process

In case 1 put T2 = 18 (instead of 22)

And then calculate a little bit by yourself

In case 2 part A put T2= 34 (instead of 31)

And then calculate

Then use that value of heat in part B

Rest of all is same

I'm currently in train so sorry i can't upload a new solution for these small changes

Hope this will be enough to help you ?

Case 1] Given L - - 1.0 m, b=1.0 m Area A = L x b= 2x1 - 2 Thicunesse d = 6.5cm - 2 0.005 m k. 0.84 W/(m²) Ti - 4°c, te 22.0c Time t = 1 min I - KA (T2-T) Seconds 60 seconds -po.sh x 2 x (22-4 - a = (6048) 60 a = 362880 J J Given A = 0.95 om? d = 2.50 cm = 0.025m kr o.olow/moc T oc Time tI 1 hour - 3600 Seconds KA (T2-T.) 3600 => . - 0.0lox0.950x (3,- – 11.78 6.oloxo-gox. 0.025 - - 3600 11-21 - (a = 42408 J (Ani)

(b) Giren Latent heat of fusion - 3. 4x 103 lug We know a-mol (m-mass of ice i. 42408 - mx 3.4x10s. - m- 42408 3. 4x los - n = 0.125 kg (Ans) o. 125 kg ice melts in 1 hour,