Question

Problem 3 In a laboratory consolidation test on a representative sample of cohesive soil, the original height of a double-dra

0 0
Add a comment Improve this question Transcribed image text
Answer #1

35 4mm Sample Col Height ofDouble drained Original Conolidation Degnee t 5min 300 sec Consolidasion for Timme H= 15 m-15,O0 0that Kmow We Cv t factor Tv Time Similaor Pubjectud Layin As Sample & are Loading: imow thcd We factor TV Time 100 . For 50 C25 4 ampe -the For Luu t \ = tor 50. Consoliclaln Sample 300 sec For Cv t Ty d2- Cv ( 300 O193 (12-)2 Cu 0 10 55 Co- et ficie(OR) Landing Brainage Conditions Similar For Settlernent at 2, H, 2 2 254/1 300 /00091 Sec - (0나.C25x t2 s 3. 317 Given FinalCv t T= d2 phere Cv01055 O1055x t O O314 2 15 1D0O C Sec t 1 75 x (D 3.86 days attain 4cm takem to Time ot Consolidation (93

Add a comment
Know the answer?
Add Answer to:
Problem 3 In a laboratory consolidation test on a representative sample of cohesive soil, the original height of a d...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 2. A consolidation test was made on a sample of saturated clay in a circular ring with a height o...

    2. A consolidation test was made on a sample of saturated clay in a circular ring with a height of 1.22 inches and an area of 4.91 square inches. Primary consolidation under the addition of each load was essentially complete at the end of 24 hours. The dial readings corresponding to the end of primary consolidation under each load increment are provided below. The initial void ratio was 1.70 Dial Reading (inch x 10 Pressure (tsf) 0.000 0.064 0.131 0.264...

  • Laboratory tests on a 2.5 cm thick clay sample that is drained on both sides indicates...

    Laboratory tests on a 2.5 cm thick clay sample that is drained on both sides indicates that 50% consolidation occurs after 8.5 minutes (a) How long will it take for 50% consolidation for the same clay in the field that is 4 m thick but drained at the top only? (b) Find the time required for the same clay layer in Part (a) to reach 65% consolidation.

  • soil Q1) An oedometer test was performed on a 2 cm thick clay sample drained on...

    soil Q1) An oedometer test was performed on a 2 cm thick clay sample drained on both sides taken from the mid clay layer shown below, after 10 minutes 50% consolidation is reached . a) How long time in days would the same degree of consolidation(50%) be reached in the field ?. b) How much the Final settlement would be reached in the clay layer.? c) How much the preconsolidation pressure of a specimen. ? 3m 2m Sand surcharge Y...

  • soil mechanics Q1) An oedometer test was performed on a 2 cm thick clay sample drained...

    soil mechanics Q1) An oedometer test was performed on a 2 cm thick clay sample drained on both sides taken from the mid clay layer shown below, after 10 minutes 50% consolidation is reached. a) How long time in days would the same degree of consolidation(50%) be reached in the field ? b) How much the final settlement would be reached in the clay layer.? c) How much the preconsolidation pressure of a specimen. ? Sm 2m Sand surcharge y...

  • The time for 50% consolidation of a 25 mm thick clay specimen (drained at top and bottom) in the laboratory is 1...

    The time for 50% consolidation of a 25 mm thick clay specimen (drained at top and bottom) in the laboratory is 150 sec. How long (in days) will it take for a 3 m thick layer of the same clay in the field under the same pressure increment to reach 75% consolidation? There is an impermeable shale layer at the bottom of the clay layer in the field I. 2. Use Figure 1 for the following Compute the vertical effective...

  • The oedometer test data below was obtained from a sample of a clay soil when the...

    The oedometer test data below was obtained from a sample of a clay soil when the loading increased from 200 to 400 kN/m² (Table Q8a). Table Q8a Time (min) Time (min) 0.00 0.25 1.00 2.25 4.00 Height (mm) 19.600 19.349 19.178 19.008 18.851 18,727 18.643 18.587 Height (mm) 18.555 18.515 18.505 18.497 18.490 18.483 18.477 18.449 6.25 9.00 12.25 100 400 (a) Using the 'square root of time method' determine the following: immediate compression (mm) primary consolidation (mm) coefficient of...

  • Figure P3 shows the soil profile at a site for a proposed office building. It is...

    Figure P3 shows the soil profile at a site for a proposed office building. It is expected that the vertical stress at the top of the clay will increase by 150 kPa and at the bottom by 90 kPa. Assurning a linear stress distribution within the clay: (a) Calculate the consolidation settlement. You should divide the clay into five layers, compute the settlement for each layer, and then find the total settlement. Assume G = 2.7 for both sand and...

  • mblem No. 3 ( 30%) A steel eil tank with flexible foundation, 50m diameter and 12m height has oil y-9.42 kN The foundation soil is 3.3m of sand Ф.35° and Y-18.85 kNm' overlaying a layer of un...

    mblem No. 3 ( 30%) A steel eil tank with flexible foundation, 50m diameter and 12m height has oil y-9.42 kN The foundation soil is 3.3m of sand Ф.35° and Y-18.85 kNm' overlaying a layer of uniform. armally consolidated clay of 17tn thick with Ф-10° and Y-17.3 kN/m.c_ 12 kNtn.c -127 and C-04 underlain by another layer of sand. The water table is at the surface level. Oedometer test on a 2.54cm thick, doubly-drained sample from the clay stratum attained...

  • 9 The data shown in the table below were obtained from a laboratory consolidation test on...

    9 The data shown in the table below were obtained from a laboratory consolidation test on a normally consolidated undisturbed MH soil with a liquid limit of 65. The sample was 62 mm in diameter, 25 mm tall and was tested under a double drainage condition Compute c, using the square root of time fitting method Time Since Loading (HH:MM:SS) 00:01:01 Dial Reading (mm) 7.21 7.74 00:03:06 00:08:35 00:16:39 8.40 9.01 9.60 00:30:15 00:59:17 10.11 01:54:29 10.35

  • help with problems 1 & 2 please and explain Problem 1 A deposit of Swedish clay...

    help with problems 1 & 2 please and explain Problem 1 A deposit of Swedish clay is 15 m thick drained at both top and bottom. The coefficient of consolidation for the clay layer was estimated to be 1 x 10 cm/sec from laboratory test. The ultimate consolidation settlement (Sc) was calculated under the applied load in the field and was found 80 cm. Find the following: a) How long would it take for settlement of 40 cm and 70...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT