What is the volume of oxygen gas released in the decomposition of 35.62 g of potassium chlorate at STP?
KClO3 (s) ---> KCl (s) + O2 (g)

What is the volume of oxygen gas released in the decomposition of 35.62 g of potassium chlorate at STP? KClO3 (s) --->...
The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory 2KCIO3 (8) ► 2KCI (s) + 302 (9) What volume (L) of O2 gas at 25°C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)? Select one: a. 11 b.4.5 CO d. 3.7 e. 2.3
The decomposition of 1.500 g of potassium chlorate evolved 405 mL of oxygen gas. If the calculated volume of oxygen gas is 411 mL, what is the percent yield?
(3) Potassium chlorate (KCIO3) is known to decompose into potassium chloride (KCl) and oxygen gas (O2) upon heating: 2KCIO3 → 2KCl + 302 Suppose 10.0g of potassium chlorate is heated to complete decomposition. What is the volume of oxygen gas produced at room temperature (25°C) and atmospheric pressure (1.00 atm)? {R = 0.0821 L'atm/K mol}
The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory. 2 KCIO3 (s) --> 2 KCl (s) + 3 O2 (9) What volume (L) of O2 gas at 25°C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO 3 (s)? Select one: 0 a. 2.2 L O O O b. 4.5 L C. 11 d. 7.5 L e. 3.7 L
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 98.6 g KClO3(s). mass:
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 48.8 g KClO3(s).
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s) . The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 70.4 g KClO3(s) STRATEGY: Convert the mass of KClO3 to moles. Convert the number of moles of KClO3 to the number of moles of O2 . Convert the number of moles of O2 to grams. Step 1: 70.4 g KClO3 is equal to 0.574 mol KClO3...
Solid potassium chlorate (KClO3) decomposes into potassium chloride and oxygen gas when heated. How many moles of oxygen form when 55.3 g completely decomposes? 0.338 mol 0.677 mol 0.451 mol 83.0 mol
Oxygen gas can be prepared by heating potassium chlorate: 2KClO3(s)2KCl(s) + 3O2(g) In one experiment, a sample of KClO3 reacts and the gas produced is collected by water displacement. The gas sample has a temperature of 23.00 °C, a volume of 769.0 mL, and a pressure of 742.0 mm Hg. Calculate the amount (in moles) of oxygen gas produced in the reaction. The vapor pressure of water is 21.07 mm Hg at 23.00 °C.
Percentage of Oxygen in Potassium Chlorate Introduction: The thermal decomposition of potassium chlorate can be described by the following equation: 2 KCIO3(s) 2 KCls) + 3 O2(g) Egn 1 (D stands for heating, elevated temperature) In this experiment you will determine the percentage of oxygen in potassium chlorate. You will compare the experimental result with the theoretical percentage calculated from the formula KCIO3. While potassium chlorate decomposes simply by heating, the reaction is very slow. A catalyst is used. Catalyst...