Question

Write a bash script that accepts one command line argument 'a' which is an integer between 1 and 50 inclusive. It should output a list of integers from 'a' and ending with '1' according to the following iteration rule. ( fx = x/2 if x is even; fx=3x+1 if x is odd )

Answer 1

#!/bin/bash

if [ $# -ne 1 ]

then

echo "You need to enter one argument"

else

echo "You have entered" $1

value="$1"

i=0

while [ $value -gt 1 ]

do

rem=$(( $value % 2 ))

if [ $rem -eq 0 ]

then

value=$(( value / 2 ))

array[$i]=$value

else

value=$((( 3 * value) + 1))

array[$i]=$value

fi

i=$((i+1))

done

echo ${array[@]}

fi

Code and output:

11:50 AM Terminal Open Save 1 #!/bin/bash vipul@ubuntu: ~/shell 3 if S# - ne 1 ] vipul@ubueentu : ~/shell$ chmod 755 series.sh vipul@ubuntu : ~/shell$ vipul@ubentu:~/shell$ ./series.sh You need to enter one argument then echo "You need to enter one arqument" 4 6 else echo "You have entered" $1 7 8 vipul@ubuntu : ~/shell$./series.sh 7 You have entered 7 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1 vipul@ubuntu: ~/shell$ vipul@ubuntu : ~/shell$ ./series. sh 10 You have entered 10 5 16 8 4 2 1 vipul@ubuntu : ~/shell$ vipul@ubuntu:~/shell$ value-"$1" 10 11 i-0 while [ $value -gt 1 ] do 12 rem-$($value % 2 )) if Srem - eq 0] then 14 15 16 value-$(value / 2 )) array[$i] Svalue 17 18 19 20 21 22 23 else value-$(C3 * value) 1)) array [$i]-$value fi i=$C(i+1)) a 25 done 26 27 28 29 fi echo $farray [ @] }