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Question 3 1 pts Youre provided with a bottle labled [CoCl26H20] = 0.045 Min 4.60 M HCI. You heat a small volume of the solu
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Solution :- Given that in fcocla H₂0 Hel (coche? ] 20.045 M at 50° c 4.60ML J -0.046 M a 50c The relation between [cock 6tho]Qo) 20.76 M. Cel SO143 Maluc (et-cax)] =0193 M at 4°c . Fcoche]2- = 0.306 M (co Cheol)a* (coce.620) = 0.76M (21 -0.193 M -TheFwilibrium constant, ko (cocle- (cocho]+(!? = 0.041 O2012 ( 18) 2 OOH! 0.234 0175 AGO = 8.31434 moł x 323 k. xo. 175 = 469.95216 AG = 469.95 J mo + (8-314 TK Smolx276* 40.) -- 469.95 J mol- + 24805:31 = 25275.86 I molt = a5 a75 ks molt Hence the v

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